You have 150 g of water (m). The specific heat of the water is 4.184 g/jC (c) . You heat the water and raise the temperature by
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Answer: a) The concentration after 8.8min is 0.17 M
b) Time taken for the concentration of cyclopropane to decrease from 0.25M to 0.15M is 687 seconds.
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) concentration after 8.8 min:
b) for concentration to decrease from 0.25M to 0.15M