Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
Anything that doesn't have to do with food (including water), shelter, or clothing.
For Example: Going to the pool is not a need, going on vacation is not a need etc. etc.
Hope this helps
Explanation:
Answer:
This is correct. And to remove the confusion, I am adding the meaning of the Pseudocode. You need to begin with the algo that you are working upon, and then you need it to phrase the algo with the words which are easy to be transcribed in the form of the computer instructions. Now you need to indent the instructions properly inside the loop or within the conditional clauses. And while doing this, you need to not use the words which are used in certain forms of computer language. However, IF and THEN and ELSE and ENDIF are very frequently used as pseudo-code. Hence, your answer is correct.
Explanation:
Please check the answer section.
