Answer:
Explanation:
The detailed analysis, with free body diagram and step by step calculations with appropriate substitution is as shown in the attached files.
Answer:
first step here is to substitute the 3 of your two equations into the second;
3 Ne^(-Q_v/k(1293)) = Ne^(-Q_v/k(1566))
Since 'N' is a constant, we can remove it from both sides.
We also want to combine our two Q_v values, so we can solve for Q_v, so we should put them both on the same side:
3 = e^(-Q_v/k(1293)) / e^(-Q_v/k(1566))
3 = e^(-Q_v/k(1293) + Q_v/k(1566) ) (index laws)
ln (3) = -Q_v/k(1293) + Q_v/k(1566) (log laws)
ln (3) = -0.13Q_v / k(1566) (addition of fractions)
Q_v = ln (3)* k * 1566 / -0.13 (rearranging the equation)
Now, as long as you know Boltzmann's constant it's just a matter of substituting it for k and plugging everything into a calculator.
Answer:
Engineers are people that design and create things to better the human and natural worlds.Engineers Create Buildings and structures that serve different purposes One could be an architect someone who designs buildings, or maybe a mechanical engineer and create refrigerators and phones.
Explanation:
Answer:
A
Explanation:
because Farmers in hilly areas grow crops on terraces built on the hillsides.
Answer:
61.5 °C
Explanation:
The resistance of the relay coil at 15 °C is R = V/I = 6/0.12 = 50 ohms. In order for the coil current to remain above 0.10 A, the resistance must remain below R = 6/0.10 = 60 ohms.
At some temperature difference ΔT from 15 °C, the resistance of the coil will be ...
R = R0(1 +α·ΔT)
where R0 is the resistance at 15 °C, α is the temperature coefficient of resistance, and ΔT is the temperature change. We want to solve this for ΔT:
R/R0 = 1 +α·ΔT
(R/R0 -1)/α = ΔT = (60/50 -1)/0.0043 ≈ 46.5 . . . . °C
The relay may fail to operate at temperatures above (15 +46.5) °C = 61.5 °C.