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Anarel [89]
3 years ago
5

You are to assess the biomechanics of a male’s arm using his bicep to hold a 20 kg object in his hand. The upper arm is perpendi

cular to the ground while the forearm is parallel to the ground. The male’s forearm is 26.5 cm long and weighs 1.42 kg. The man’s hand weighs 0.54 kg and is 19 cm long. The center of masses for the forearm and hand are 43% and 50% of the extremity lengths from the proximal joint, respectively.
You may assume that only the bicep generates the force, the angle between the bicep and forearm is 75 degrees, and the bicep insertion is 5cm from the elbow joint.

a) Draw a complete free body diagram of the above described activity. (5 pts)

b) Calculate the elbow moment due to external load and body segments weight. (5 pts)

c) Calculate the elbow contact force and force exerted by the bicep. (5 pts)

Engineering
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

Explanation:

The detailed analysis, with free body diagram and step by step calculations with appropriate substitution is as shown in the attached files.

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What type of spring is mounted on a mcpherson strut suspension system?
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Coil Spring

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6 0
2 years ago
A flat plate 1.5 m long and 1.0 m wide is towed in water at 20 o C in the direction of its length at a speed of 15 cm/s. Determi
beks73 [17]

Answer:

15.8

0.0944

Explanation:

L = 1.5

B = 1.0

Speed of water = 15cm

Temperature = 20⁰C

At 20⁰C

Specific weight = 9790

Kinematic viscosity v = 1.00x10^-4m²/s

Dynamic viscosity u = 1.00x10^-3

Density p = 998kg/m²

Reynolds number

= 0.15x1.5/1.00x10^-4

= 225000

S = 5

5x1.5/225000^1/2

= 0.0158

= 15.8mm

Resistance on one side of plate

F = 0.664x1x1.0x10^-3x0.15x225000^1/2

= 0.04724N

Total resistance

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3 0
3 years ago
The best grade of hardwood lumber that is generally available is _____​
Vesnalui [34]

Answer:

FAS

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first and second grade

5 0
2 years ago
A stream leaving a sewage pond (containing 80 mg/L of sewage) moves as a plug with a velocity of 40 m/hr. A concentration of 50
Leno4ka [110]

Answer:Decay rate constant,k  = 0.00376/hr

Explanation:

IsT Order  Rate of reaction is given as

In At/ Ao = -Kt

where [A]t is the final concentration at time  t  and  [A]o  is the inital concentration at time 0, and  k  is the first-order rate constant.

Initial concentration = 80 mg/L

Final concentration = 50 mg/L

Velocity = 40 m/hr

Distance= 5000 m

Time taken = Distance / Time

              5000m / 40m/hr = 125 hr

In At/ Ao = -Kt

In 50/80 = -Kt

-0.47 = -kt

- K= -0.47 / 125

k = 0.00376

Decay rate constant,k  = 0.00376/hr

8 0
3 years ago
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