Answer:
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Explanation:
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Answer:
initial quality = 0.3690
heat transfer = 979.63 kJ/kg
Explanation:
Given data:
volume of tank 0.45^3
weight of water 12 kg
Initial pressure 20 bar
final pressure 4 bar
Specific volume
At Pressure = 20 bar, from saturated water table
inital quality is x =0.3690
Heat transfer is calculated as
from saturated water table, for pressure 20 bar ,
=908.79 + 0.0357(1890.7)
= 979.63 kJ/kg
Answer:
The required pumping head is 1344.55 m and the pumping power is 236.96 kW
Explanation:
The energy equation is equal to:
For the pipe 1, the flow velocity is:
Q = 18 L/s = 0.018 m³/s
D = 6 cm = 0.06 m
The Reynold´s number is:
Using the graph of Moody, I will select the f value at 0.0043 and 335339.4, as 0.02941
The head of pipe 1 is:
For the pipe 2, the flow velocity is:
The Reynold´s number is:
The head of pipe 1 is:
The total head is:
hi = 1326.18 + 21.3 = 1347.48 m
The required pump head is:
The required pumping power is:
Normal Stress = 200 units / Area of the tube face
Normal Stress is equal to the force applied perpendicular to the surface area divided by the surface area. This force is also known as the axial load.
Therefore, we get the following formula:
Normal Stress = 200 units of Force / Area of the tube face
Answer:
a. 3.17*10¹⁹ b. 3.17*10¹⁴
Explanation:
a. Area A = 1cm²
Thickness h = 0.1cm
Energy of photon E = hf=hc/λ
Where f = frequency; c=speed of light; λ=wavelength = 6300Α=6300*10⁻¹⁰;
Planck's constant h = 6.626*10⁻³⁴ joule-seconds; speed of light c = 3*10⁸
Therefore E = (6.626*10⁻³⁴)*3*10⁸/6300*10⁻¹⁰=3.155*10¹⁹J
1Watt of light releases 3.17*10¹⁸ photons per second.
Volume of sample = Area * Thickness = 1*0.1=0.1cm³
Therefore, number of electron hole pairs that are generated per unit volume per unit time = 3.17*10¹⁸/0.1 = 3.17*10¹⁹photon/cm³-s
b. Steady state excess carrier concentration = 3.17*10¹⁹*10μs
=3.17*10¹⁹*10*10⁻⁶
=3.17*10¹⁴/cm³