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otez555 [7]
2 years ago
10

Limited time only for christmas give yourself free 100 points YES YES muhahahahhaha

Engineering
2 answers:
Paraphin [41]2 years ago
8 0

Answer:

How to

Explanation:

e

Setler79 [48]2 years ago
6 0
Answer:

Thank you so much and may god bless you.
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Explanation:

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7 0
3 years ago
The shear flow at the point depends on the value of Q for the portion of the upper flange to the right of the point. Calculate t
Ostrovityanka [42]

Q)The shear flow at a point is given by q = 1 of 2 An I-beam has a flange width b = 200 mm , height h = 200 mm , web thickness tw = 8 mm, and flange thickness t = 12 mm, For the given point The shear flow at the point depends on the value of Q for the portion of the upper flange to the right of the point. Calculate the value of Q. Express your answer with appropriate units to three significant figures.( <u>I have also attached the diagram for better understanding)</u>

Answer:

Q = 56400 mm^3

Explanation:

<u>I have given the explanation in the attached file below.</u>

6 0
3 years ago
provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its worki
Vaselesa [24]

Answer:

hello some parts of your question is missing attached below is the missing part ( the required fig and table )

answer : The solar collector surface area = 7133 m^2

Explanation:

Given data :

Rate of energy input to the collectors from solar radiation = 0.3 kW/m^2

percentage of solar power absorbed by refrigerant = 60%

Determine the solar collector surface area

The solar collector surface area = 7133 m^2

attached below is a detailed solution of the problem

8 0
3 years ago
Write a function called largest3 which takes 3 numbers as parameters and returns the largest of the 3. Write a program which tak
tamaranim1 [39]

Answer:

The solution code is written in Python.

  1. def largest3(num1, num2, num3):
  2.    largest = num1
  3.    if(largest < num2):
  4.        largest = num2
  5.    
  6.    if(largest < num3):
  7.        largest = num3
  8.    
  9.    return largest
  10. first_num = int(input("Enter first number: "))
  11. second_num = int(input("Enter second number: "))
  12. third_num = int(input("Enter third number: "))
  13. largest_number = largest3(first_num, second_num, third_num)
  14. print("The largest number is " + str(largest_number))

Explanation:

<u>Create function largest3</u>

  • Firstly, we can create a function <em>largest3 </em>which take 3 numbers (<em>num1, num2, num3</em>) as input. (Line 1).
  • Please note Python uses keyword <em>def </em>to denote a function. The code from Line 2 - 10 are function body of <em>largest3</em>.
  • Within the function body, create a variable,<em> largest</em>, to store the largest number. In the first beginning, just tentatively assign<em> num1 </em>to<em> largest</em>. (Line 2)
  • Next, proceed to check if the current "<em>largest</em>" value smaller than the<em> num2 </em>(Line 4). If so, replace the original value of largest variable with <em>num2</em> (Line 5).
  • Repeat the similar comparison procedure to<em> </em><em>num3</em> (Line 7-8)
  • At the end, return the final value of "<em>largest</em>" as output

<u>Get User Input</u>

  • Prompt use input for three numbers (Line 13 -15) using Python built-in <em>input</em> function.
  • Please note the input parts of codes is done outside of the function <em>largest3</em>.

<u>Call function to get largest number and display</u>

  • We can simply call the function<em> largest </em>by writing the function name <em>largest</em> and passing the three user input into the parenthesis as arguments. (Line 17)
  • The function <em>largest </em>will operate on the three arguments and return the output to the variable <em>largest_number</em>.
  • Lastly, print the output using Python built-in <em>print</em> function. (Line 18)
  • Please note the output parts of codes is also done outside of the function<em> largest3</em>.
6 0
3 years ago
I don't know help me​
sergey [27]

Answer:

for...?

thenks for the points :))

4 0
3 years ago
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