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otez555 [7]
2 years ago
10

Limited time only for christmas give yourself free 100 points YES YES muhahahahhaha

Engineering
2 answers:
Paraphin [41]2 years ago
8 0

Answer:

How to

Explanation:

e

Setler79 [48]2 years ago
6 0
Answer:

Thank you so much and may god bless you.
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A work element in a manual assembly task consists of the following MTM-1 elements: (1) R16C, (2) G4A, (3) M10B5, (4) RL1, (5) R1
ella [17]

Answer:

a)

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b) 3.1 secs

Explanation:

a) Determine the normal times in TMUs for these motion elements

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b ) Determine the total time for this work element in seconds

first we have to determine the total TMU = ∑ TMU = 86.4 TMU

note ; 1 TMU = 0.036 seconds

hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds

7 0
3 years ago
Many companies are combining their online business activities with an existing physical presence. In about 100 words, explain wh
Daniel [21]

Answer:

Companies are combining their online business activities with their existing physical presence in order to lower costs of their operations. When both these things are combined labor costs are reduced because with online presence the company has to have limited number of branches, inventory costs are reduced because additional inventories for every physical outlet is not required and delivery costs are reduced because now company don't have to supply the things to all the outlets on regular basis.

Trust of the people is also improved because mostly people are reluctant to order from the brands that only have their online store and donot have any physical presence. Value added services are provided by a company who have both online and offline presence like home delivery and customized offerings.

 

3 0
3 years ago
The variation of the pressure of a fluid with density at constant temperature is known as the _____.
qaws [65]

The variation of the pressure of a fluid with density at constant temperature is known as the coefficient of compressibility.

<h3>What is a compressor?</h3>

A compressor can be defined as a mechanical device that is designed and developed to provide power to refrigerators, air conditioners, and other heating or cooling mechanical devices (engines), especially by increasing the pressure on air or other applicable gases.

In an isothermal process, the coefficient of compressibility is also known as isothermal compressibility or compressibility and it refers to a measure of the variation of the pressure and relative volume of a fluid with density at constant temperature.

Read more on coefficient of compressibility here: brainly.com/question/25237713

#SPJ1

7 0
2 years ago
A skilled worker with the ability to operate computer numerically controlled (CNC) machines is qualified to work in which of the
KengaRu [80]

Answer:

Machinist

Explanation:

A skilled worker with the ability to operate computer numerically controlled (CNC) machines is qualified to work in a machinist position.

A machinist is a person who is properly skilled and consists of advanced knowledge regarding the functions of a CNC machine. He can use different mechanisms and complex numerical functions of the machine to carry out different tasks. Any person who lacks the official learning of mechanisms cannot operate such machines effectively.

3 0
3 years ago
Wind blows on the side of a fully enclosed hospital located on open flat terrain where V= 120 mi/h. Determine the external press
ss7ja [257]

Answer:

The external pressure is p = -21.9 psf or p = -8.85 psf

Explanation:

Given :

Velocity of wind, v = 120 mi / hr

$k_d = k_c =1 $   (wind direction factor)

$k _{zt} = 1 $  = topographical factor (for flat terrain)

$ q_n$ = velocity pressure at height h

$ \therefore q_n = 0.00256 k_z k_{zt} k_d v^2 $

$  q_n = 0.00256 \times  k_z (1)(1)(120)^2 $

    $ = 36.86 k_z$

But for height h = 30 ft, $ k_z$ = 0.98 (from table)

$ \therefore q_n = 36.86 \times 0.98 $

        = 36.16

Now, $ \frac{L}{B}= \frac{200}{200} =1$ ,   so $C_p=-0.5 $ (from table)

$p = q(G)(C_p)-q_n(GC_{pi})$

where, p = external pressure

            G = 0.85 = gust factor (for typical rigid building)

            $GC_{pi} = \pm 0.18 $   (internal pressure co efficient)

Therefore putting the values,

$p = (36.13)(0.85)(-0.5)-(36.13)(\pm 0.18)$

p = -21.9 psf or p = -8.85 psf

4 0
4 years ago
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