Answer:
design hour volumes will be 4000 to 6000
Explanation:
given data
AADT = 150000 veh/day
solution
we get here design hour volumes that is express as
design hour volumes = AADT × k × D ..............1
here k is factor and its range is 8 to 12 % for urban
and D is directional distribution i.e traffic equal divided by the direction
so here design hour volumes will be 4000 to 6000
Answer Explanation:
the efficiency of the the engine is given by=1-
where T₂= lower temperature
T₁= Higher temperature
we have given efficiency =70%
lower temperature T₂=27°C=273+27=300K
higher temperature T₁=627°C=273+627=900K
efficiency=1-
=1-
=1-0.3333
=0.6666
=66%
66% is less than 70% so so inventor claim is wrong
Answer:
Diesel cycle:
All diesel engine works on diesel cycle.It have four processes .These four processes are as follows
1-2.Reversible adiabatic compression
2-3.Heat addition at constant pressure
3-4.Reversible adiabatic expansion
4-1.Heat addition at constant volume
When air inters in the piston cylinder after that it compresses and gets heated due to compression after that heat addition take place at constant pressure after that power is produces when piston moves to bottom dead center.
From the diagram of P-v And T-s we can understand so easily.
Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb