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Aneli [31]
4 years ago
12

Clarisse is an architect. What skills will she apply to integrate her visualized solutions with other aspects such as business a

nd industry standards?
Engineering
1 answer:
Allushta [10]4 years ago
5 0

Answer:Given h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.

Explanation:

vGiven h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.Given h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.Given h(x)=4x-4h(x)=4x−4, solve for xx when h(x)=0h(x)=0.

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Do plastic materials have high or low ductility? Explain why.​
Flura [38]
The impact behavior of plastic materials is strongly dependent upon the temperature. At high temperatures, materials are more ductile and have high impact toughness. At low temperatures, some plastics that would be ductile at room temperature become brittle.
3 0
3 years ago
I WILL GIVE 20 POINTS!!
Alex777 [14]

Answer:

Use a resume header

Explanation:

Create a Summary

Research industry, employer keywords

there are some hints okay

5 0
3 years ago
Read 2 more answers
An inventor claims to have developed a refrigerator that at steady state requires a net power input of 1.1 horsepower to remove
Lynna [10]

Answer:

The inventor's claim is false in the sense that no thermal machine can violate the first thermodynamic law.

Explanation:

The inventor's claim could not be possible as no thermal machine can transfer more heat than the input work consumed. If we expose the thermal efficiency:

n=Q out / W in

Where Q and W both must be in the same power unit, so we will convert the remove heat from BTU/hr to hp:

12000 BTU/hr = 4.72 hp

Therefore by comparing, we notice that the removing heat of 4.75 hp is large than the delivered work of 1.11 hp. By evaluating the efficiency:

[tex]n=4.75 hp / 1.1 hp  = 4.3 > 1[/tex]

6 0
3 years ago
In a steam power plant, 1 MW is added in the boiler, 0.58 MW is taken out in the condenser and the pump work is 0.02 MW.
Free_Kalibri [48]

Answer:

a) \eta = 42\,\%, b) COP_{R} = 29

Explanation:

a) The thermal efficiency is:

\eta = \frac{\dot Q_{in} - \dot Q_{out}}{\dot Q_{in}}\times 100\,\%

\eta = \frac{1\,MW-0.58\,MW}{1\,MW} \,\times 100\,\%

\eta = 42\,\%

b) The coefficient of performance is:

COP_{R} = \frac{\dot Q_{L}}{\dot W}

COP_{R} = \frac{0.58\,MW}{0.02\,MW}

COP_{R} = 29

3 0
3 years ago
What is the last step to the design process?
ryzh [129]

Answer:

B: Present solution

4 0
4 years ago
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