The reaction is low b/c of the tempature. that's why.
Answer:
1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.
Explanation:1 mol Al. 26.9815 g Al. ×. 2 mol AlCl. 3. 2 mol Al. =0.100 mol AlCl3. The balanced equation says: 3 mol Cl2 produces ... that the initial mass of Al was larger than required to react with all of the Cl2. The sum of the masses.
Answer:
0.4694 moles of CrCl₃
Explanation:
The balanced equation is:
Cr₂O₃(s) + 3CCl₄(l) → 2CrCl₃(s) + 3COCl₂(aq)
The stoichiometry of the equation is how much moles of the substances must react to form the products, and it's represented by the coefficients of the balanced equation. So, 1 mol of Cr₂O₃ must react with 3 moles of CCl₄ to form 2 moles of CrCl₃ and 3 moles of COCl₂.
The stoichiometry calculus must be on a moles basis. The compounds of interest are Cr₂O₃ and CrCl₃. The molar masses of the elements are:
MCr = 52 g/mol
MCl = 35.5 g/mol
MO = 16 g/mol
So, the molar mass of the Cr₂O₃ is = 2x52 + 3x35.5 = 210.5 g/mol.
The number of moles is the mass divided by the molar mass, so:
n = 49.4/210.5 = 0.2347 mol of Cr₂O₃.
For the stoichiometry:
1 mol of Cr₂O₃ ------------------- 2 moles of CrCl₃
0.2347 mol of Cr₂O₃----------- x
By a simple direct three rule:
x = 0.4694 moles of CrCl₃
Answer:
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Explanation:
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Answer:
b. A mole of chlorine gas contains 2 (6.02 * 10^23 ) atoms.
c. A mole of carbon dioxide contains two moles of oxygen molecules (CO2)
e. A mole consists of the number of particles in exactly 12g of naturally occurring carbon.
Explanation:
A mole of oxygen gas (O2) contains 2 (6.02 * 10^23) atoms
A mole of Ammonia gas (NH3) has a mass of 17.031g/mol
A mole is defined as the unit used in measurement of the amount of substances in the International System of Units.
A mole was initially defined as the number of particles in exactly 12g of naturally occurring carbon.
Therefore, options b, c and e are correct
