In the titration of acetic acid with a strong base NaOH, the concentration of acetic acid is determined using the volume and molar concentration of NaOH used for titrating the vinegar solution. NaOH and acetic acid react in 1:1 mole ratio.
When a drop of the strong base, dispensed from the buret sticks to the walls of the Erlenmeyer flask but is not washed into the flask containing vinegar, it means that the recorded value of NaOH dispensed will be higher than the actual value required for the titration. So, the reported moles of acetic acid calculated from the moles of NaOH used for the titration will be higher. So, the mass percent reported will be higher than the actual value.
The number of valence electrons of an element can be determined by the periodic table group (vertical column) in which the element is categorized
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With increase in the depth of the soil the temperature of soil also get increases due to high pressure present deep in the earth.
With high temperature, the metal that having high melting point such as heavy metals are present which includes lead, chromium, arsenic, zinc, cadmium, mercury etc. With incresae in depth the soil get contaminated with these heavy metal or the concentration of heavy metal may increases in soil with increase in depth which may result in low fertility of soil. Heavy metal also increases toxicity of the soil which affect the growth of crops and plants by harming the roots of flora.
Certain bacteria such as thermoacidophilus also present at this depth fo earth as they can survive in this range of temperature.
Thus, the condition of soil present more than 50 km deep in earth is not good in comparison to fresh soil present on surface.
Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane