Question:
Charlotte has been working for her company for x years. Travis has been working for the same company exactly 3 years longer than Charlotte. What is the range of the relationship?
A- y>0
B- y>3
C. y<3
D. 0
Answer:
y > 3
Step-by-step explanation:
Number of years Charlotte has worked = x
Number of years Travis has worked = y. ie, y = 3+x
Let's assume the function reaches its lowest point at 3. There could also be a higher value for this function.
We now have:
f(x) = y > 3
Since Travis has been working for the same company exactly 3 years longer than Charlotte the range of the relationship is y>3
Answer:
x = e^2/2 + 3
Step-by-step explanation:
Solve for x:
log(2 x - 6) = 2
Hint: | Eliminate the logarithm from the left hand side.
Cancel logarithms by taking exp of both sides:
2 x - 6 = e^2
Hint: | Isolate terms with x to the left hand side.
Add 6 to both sides:
2 x = e^2 + 6
Hint: | Solve for x.
Divide both sides by 2:
Answer: x = e^2/2 + 3
Uhh, answer choices?
In any case, since 
is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, 
Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so 
Let’s assume that Laura has x$
Jose = 8+ x
Keith= 3x
So the total is equal to
118= x + 8 +x + 3x
118= 5x + 8
Subtract 8 from both sides
110= 5x
Divide 5 by both sides
22$= x which is what Laura has
Jose will have :8+22= 30$
Keith will have :3*22=66$
