Explanation:
38 ATP molecules May be produced from glucose
Answer:
6.02 x 10²⁰ molecules
Explanation:
Given parameters:
Volume of nitrogen = 120cm³
Unknown:
Mass of Nitrogen = ?
Number of molecules present in it = ?
Solution:
At STP;
1 mole of a substance contains 22.4dm³ particles
100cm³ = 1dm³
24cm³ will give 0.024dm³
22.4dm³ of particles are in 1 mole of substances at STP
0.024dm³ of particles will contain = 0.001mole
Mass of Nitrogen = Number of moles x molar mass
molar mass of nitrogen = 14g/mol
Mass of nitrogen = 0.001 x 14 = 0.014g
Number of molecules present;
1 mole of a substance contains 6.02 x 10²³ molecules
0.001 mole of Nitrogen will contain 0.001 x 6.02 x 10²³ = 6.02 x 10²⁰
6.02 x 10²⁰ molecules
<span>If the aqueous solution is 34% Licl then it is 100 - 34% water = 66%
From the calculation we've found out that it is 66% water. Then we need to find the weight from a 250 g solution.
66/100 * 250 = 165g
Hence it is 165g</span>
When exercising, we respire. When we do not do exercise that often, our muscles will not be able to withstand long amounts of exercise due to lack of oxygen. This is called Anaroebic Respiration. This is when glucose turns to Lactic Acid immediately. Anaerobic respiration releases less energy.
For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:
R₁/R₂ = √(M₂/M₁)
Let 1 be N₂ while 2 be Cl₂
255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s
<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>