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Schach [20]
3 years ago
13

Charlie the Chemist heats a 62.51 g piece of copper from 22.9°C to 345.0°C. Calculate the amount

Chemistry
1 answer:
Ivanshal [37]3 years ago
6 0
  • Mass=m=62.51g
  • Initial temperature=T_i=22.9°C
  • Final temperature=T_f=345.0°C
  • Specific heat of copper=0.0920cal/g°C
  • ∆T=T_f-T_i=345-22.9=322.1°C

\\ \tt\hookrightarrow Q=mc\Delta T

\\ \tt\hookrightarrow Q=62.1(0.0920)(322.1)

\\ \tt\hookrightarrow Q=1840.22172cal

\\ \tt\hookrightarrow Q=1840.222cal

\\ \tt\hookrightarrow Q=1840.2cal

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A 15.0 ml sample of gas at 10.0 degree Celsius and 760 torr changes to a pressure of 1252 torr at 35.0 degree Celsius. What is t
netineya [11]

Answer:

9.91 mL

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (torr)

P2 = final pressure (torr)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 15.0mL

V2 = ?

P1 = 760 torr

P2 = 1252 torr

T1 = 10°C = 10 + 273 = 283K

T2 = 35°C = 35 + 273 = 308K

Using P1V1/T1 = P2V2/T2

760 × 15/283 = 1252 × V2/308

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Cross multiply

11400 × 308 = 283 × 1252V2

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4 0
3 years ago
A student needs to prepare 100. mL of 0.612 M Cu(NO3)2 solution. What mass, in grams, of copper(II) nitrate should the student u
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Answer: 11.5 grams

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where,

Morality = 0.612 M

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V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

0.612=\frac{n\times 1000}{100ml}

n=0.0612moles

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Marat540 [252]

Answer:

.75 meter north

Explanation:

v = d/t

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v = .75

7 0
3 years ago
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