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3 years ago

12

which of the following trigonometric expressions are equal? a. sin(theta) b. cos(theta)tan(theta) c. 1/sec(theta) d. csc(theta)

(1-cos^2(theta))

1 answer:

zimovet [89]3 years ago

5 0

Answer:

A & B

Step-by-step explanation:

cos(theta)tan(theta) can be expressed as;

cos(theta)tan(theta) = cos(theta) × (sin(theta))/cos(theta).

cos(theta) cancels out to give; sin(theta)

Thus is equivalent to option A

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