A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle θ below the horizontal,
1 answer:
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Answer:
Electric flux,
Explanation:
It is given that,
Electric field,
We need to find the electric flux through a circular area of radius 2.66 m that lies in the xy-plane.
The electric flux is given by :
Since, k.k=i.i=j.j = 1
So,
So, the electric flux through a circular area is .Hence, this is the required solution.
Explanation:
The given data is as follows.
Fluid is water so, density
Weight flow rate = 500 lbf/s = 2224.11 N/sec
Cross-sectional area (A) =
= 0.05184
Hence, weight flow rate will be given as follows.
w =
2224.11 N/sec =
V = m/s
= 4.373 m/s
Thus, we can conclude that average velocity in the given case is 4.373 m/s.