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riadik2000 [5.3K]
2 years ago
14

A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle θ below the horizontal,

and the box remains a rest. The box rests on a horizontal surface that has some friction with the box. The normal force on the box due to the floor is equal to
Physics
1 answer:
Kipish [7]2 years ago
3 0

Answer:

its on wheels and they are supposed to make it eas

Explanation:

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What type of energy slows down
Tema [17]
It is Potential energy it's at rest
4 0
3 years ago
A body accelerates uniformly from rest at 2ms² for 5 seconds . calculate its average velocity in this time.​
timama [110]

Answer:

0.4

Explanation:

average velocity =d/t

2/5=0.4

0.4m

7 0
3 years ago
A turntable, with a mass of 1.5 kg and diameter of 20 cm, rotates at 70 rpm on frictionless bearings. Two 540 g blocks fall from
ivann1987 [24]

Answer:

The turntable's angular speed after the event is 28.687 revolutions per minute.

Explanation:

The system formed by the turntable and the two block are not under the effect of any external force, so we can apply the Principle of Conservation of Angular Momentum, which states that:

I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f} (1)

Where:

I_{T} - Moment of inertia of the turntable, in kilogram-square meters.

r - Distance of the block regarding the center of the turntable, in meters.

m - Mass of the object, in kilograms.

\omega_{o} - Initial angular speed of the turntable, in radians per second.

\omega_{f} - Final angular speed of the turntable-objects system, in radians per second.

In addition, the momentum of inertia of the turntable is determined by following formula:

I_{T} = \frac{1}{2}\cdot M\cdot r^{2} (2)

Where M is the mass of the turntable, in kilograms.

If we know that \omega_{o} \approx 7.330\,\frac{rad}{s}, M = 1.5\,kg, m = 0.54\,kg and r = 0.1\,m, then the angular speed of the turntable after the event is:

I_{T} = \frac{1}{2}\cdot M\cdot r^{2}

I_{T} = 7.5\times 10^{-3}\,kg\cdot m^{2}

I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}

\omega_{f} = \frac{I_{T}\cdot \omega_{o}}{2\cdot r^{2}\cdot m +I_{T}}

\omega_{T} = 3.004\,\frac{rad}{s} (28.687\,\frac{rev}{min})

The turntable's angular speed after the event is 28.687 revolutions per minute.

3 0
2 years ago
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receiv
Lina20 [59]

Explanation:

Given that,

Force with which a child hits a ball is 350 N

Time of contact is 0.12 s

We need to find the impulse received by the ball. The impulse delivered is given by :

J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m

So, the impulse is 42 N-m..

We know that he change in momentum is also equal to the impulse delivered.

So, impulse = 42 N-m and change in momentum =42 N-m.

7 0
3 years ago
What is the relationship between work and power
Mashcka [7]
Power is the rate work is usually done in.
3 0
3 years ago
Read 2 more answers
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