Answer:
Explanation:
The water droplet is initially neutral, it will obtain a 40 nC of charge when a charge of -40 nC is removed from the water droplet.
The charge on one electron, 
Let the N number of electrons have charge -40 nC, such that,
Now, mass of one electron = 
Therefore, mass of N electrons = 
It is the mass of the of the water droplet that must be removed in order to obtain a charge of 40 nC.
Let it is m times the total mass of the droplet which is 
Then,
It is the required fraction of mass of the droplet.
Answer
given,
mass of the = m₁ = 8.75 Kg
another mass of the object = m₂ = 14 Kg
distance between them = 50 cm
R₁ = 17 cm
R₂ = 50 -17 = 33 cm
a) Force applied due to the Mass 8.75 in +ve x- direction
Force applied due to mass 14 Kg in -ve x-direction
net force
F = F₁ + F₂
Using newton second law
b) As the acceleration of mass comes out to be +ve hence, the direction will be toward the mass of 8.75 Kg
Answer:
Explanation:
The detailed steps and appropriate integration and differentiation is as shown in the attached files.
au = −g − kv2
ad = −g + kv2
Answer:
0.3625
Explanation:
From the given information:
Consider the equilibrium conditions;
On the ladder, net torque= 0
Thus,
; and
However, by rearrangement;
![\mu= \dfrac{ (323 \ N) ( 10.8 \ m) \ cos 56^0 + (734 \ N) (7.46 \ m) \ cos \ 66.46^0}{\Big [(323 \ N)+(734 \ N) \Big] (10.8 \ m)}](https://tex.z-dn.net/?f=%5Cmu%3D%20%5Cdfrac%7B%20%28323%20%20%5C%20N%29%20%28%2010.8%20%5C%20m%29%20%5C%20cos%2056%5E0%20%2B%20%28734%20%5C%20N%29%20%287.46%20%5C%20m%29%20%5C%20cos%20%20%5C%20%2066.46%5E0%7D%7B%5CBig%20%5B%28323%20%5C%20N%29%2B%28734%20%5C%20N%29%20%5CBig%5D%20%2810.8%20%5C%20m%29%7D)
