What must a scientist do in order to develop a testable hypothesis?
2 answers:
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Answer:
Explanation:
Since the wires attract each other , the direction of current will be same in both the wires .
Let I be current in wire which is along x - axis
force of attraction per unit length between the two current carrying wire is given by
x
where I₁ and I₂ are currents in the wires and d is distance between the two
Putting the given values
285 x 10⁻⁶ = 10⁻⁷ x
I₂ = 16.76 A
Current in the wire along x axis is 16.76 A
To find point where magnetic field is zero due the these wires
The point will lie between the two wires as current is in the same direction.
Let at y = y , the neutral point lies
k 2 x = k 2 x
25.5y = 16.76 x .3 - 16.76y
42.26 y = 5.028
y = .119
= .12 m
Answer and Explanation:
Data provided in the question
Force = 50N
Length = 5mm
diameter = 2.0m =
Extended by = 0.25mm =
Based on the above information, the calculation is as follows
a. The Stress of the wire is
here area of circle = perpendicular to the are i.e cross-sectional i.e
=
=
Now place these above values to the above formula
= 15.92 MPa
As 1Pa = 1 by N m^2
So,
MPa = 10^6 N m^2
b. Now the strain of the wire is
=