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Tom [10]
3 years ago
7

What must a scientist do in order to develop a testable hypothesis?

Physics
2 answers:
yuradex [85]3 years ago
8 0

Answer: (APE X) Determine whether experimental observations can provide evidence to support a conclusion

Explanation:

pashok25 [27]3 years ago
3 0

Answer:

Explanation:

Ask a question that can be answered by making observations.

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Suppose you have 20% of 20/100 or 1/5. Describe how you can solve the problem using 1/5 instead of 20%.
grin007 [14]

Answer:

To calculate Percent in fraction You need to do following steps.

Divide number by 100.

=20/100

=1/5

6 0
3 years ago
Read 2 more answers
The resistance of an object to change its dynamic state called​
aleksandr82 [10.1K]
Inertia is the correct answer!
5 0
3 years ago
Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th
Mariulka [41]

Answer:

a) 0.0288 grams

b) 2.6*10^{-10} J/kg

Explanation:

Given that:

A typical human  body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance  for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = \frac{energy \ absorbed }{mass \ of \ the \ body}

= \frac{1.10*10^6*1.6*10^{-14}}{80}

= 2.2*10^{-10} \ J/kg

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) =  1.2  *2.2*10^{-10} \ J/kg

Effective dose (Sv) = 2.6*10^{-10} J/kg

 

5 0
4 years ago
A 50 kg person steps off a diving platform that is 10 meters above the water below (Olympic height). With what speed do they hit
Nookie1986 [14]

Answer:

14 m/s

Explanation:

The following data were obtained from the question:

Mass = 50 kg

Initial velocity (u) = 0 m/s

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

The velocity (v) with which the person hit the water can be obtained as shown below:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 10)

v² = 0 + 196

v² = 196

Take the square root of both side

v = √196

v = 14 m/s

Therefore, he will hit the water with a speed of 14 m/s

5 0
3 years ago
What is the slowest type of radiation?
tekilochka [14]
Velocity is the answer
3 0
4 years ago
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