The total kinetic energy of the system after collision is 223.5J
In elastic collision kinetic energy and momentum are conserved.
According to the question
mass of object a = 25kg
mass of object b = 25 kg
initial velocity of a u1 = 5.98 m/s
initial velocity of b u2 = 0
so from momentum conservation-
mau1 + mbu2 = (m1+m2)v
25kg × 5.98m/s + 25×0 = (25+25)v
v = 2.99 m/s
Now the total kinetic energy after the collision will be:
final kinetic energy = 1/2 (m1+m2) v²
= 1/2 (25+25)× (2.99)²
= 223.5 J
Thus, total kinetic energy of the system after collision is 223.5J
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Answer:
Option D => it is moving from high potential to low potential and losing electric potential energy.
Explanation:
Consider a big circle, within the circle we have force, F. That force, F is known as the Electric Field and inside the region or field or space, charged particle or object will be able to exerts force on the other objects.
Electric Field can be represented mathematically by using the formula below; E = kQ/r^2.
So, let us answer the question with what we have considered above. It is worthy of note to know that electric Field moves from a region of higher potential to a region of lower potential. So, any option that says this is correct.
But, there is only one problem and that is the fact that the question asked us about the direction of the movement of proton. Since, proton is s a positive charge, it is going to lose electric potential energy. So, Option D is correct.
It brings cold water from the bottom of the ocean.
To be able to identify that the object is in the same motion, we should find the graphs that has an increasing slope of displacement and with the constant velocity with varying time. Graphs on letter D satisfies these requirements.
<em>ANSWER: D</em>
<u>The following statements are false about collisions:
</u>
- The velocity change of two respective objects involved in a collision will always be equal.
- Total momentum is always conserved between any two objects involved in a collision.
Answer: Option B, and D
<u>Explanation:
</u>
In any collisions, equal amount of net force will be acted upon the colliding objects due to the third law of Newton, irrespective of the significance difference in mass of the objects. Similarly, they can also have different acceleration values during collision of two objects if the masses are identical.
But the statements regarding the equal change in velocity of two objects respectively involved in collision always is false, as the conservation of momentum is applicable for isolated system only. So it is true for only isolated system and not in all the systems.
The same reason goes for falsifying the fourth statement which states that total momentum is always conserved between two objects involved in a collision as this statement is only true for isolated system where the conservation of momentum can be applied. Thus the second and fourth statement is false regarding collision.