Answer:
Option 10. 169.118 J/KgºC
Explanation:
From the question given above, the following data were obtained:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1.61 KJ
Mass of metal bar = 476 g
Specific heat capacity (C) of metal bar =?
Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:
1 kJ = 1000 J
Therefore,
1.61 KJ = 1.61 KJ × 1000 J / 1 kJ
1.61 KJ = 1610 J
Next, we shall convert 476 g to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
476 g = 476 g × 1 Kg / 1000 g
476 g = 0.476 Kg
Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1610 J
Mass of metal bar = 0.476 Kg
Specific heat capacity (C) of metal bar =?
Q = MCΔT
1610 = 0.476 × C × 20
1610 = 9.52 × C
Divide both side by 9.52
C = 1610 / 9.52
C = 169.118 J/KgºC
Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC
Top left: slowing down
Top right: not moving
Bottom left: moving at a constant speed
Bottom right: speeding up
Answer:
I only speak English
Explanation:
I'm sorry can you type it in English
The linear speed of the pepperoni is 0.628 m/s. Its direction is tangential to the circle.
We know that;
v = rω
r = radius of the piece = 10 cm or 0.1 m
ω = angular velocity
We have to convert 60 revolutions per minute to radians per second
1 rev/min = 0.10472 rad/s
60 revolutions per minute = 60 rev/min × 0.10472 rad/s/1 rev/min
= 6.28 rad/s
v = 0.1 m × 6.28 rad/s
v = 0.628 m/s
The direction of this velocity is tangential to the circle.
Learn more: brainly.com/question/4612545