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MAVERICK [17]
3 years ago
8

What scenario would most likely lead to a higher level of physical fitness among people who live in a city?

Physics
1 answer:
ExtremeBDS [4]3 years ago
7 0
More people walk to school or work hope this helps
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A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.4 A runs through the wire
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Answer:

\vec{F}=0.40176 N \hat{k}

Explanation:

To calculate the force we need to use this equation

\vec{F}=\int\limits^L_0 {i(\vec{dl}\times\vec{B})}

where L is the total length of the wire

So in this case the small element of current is

\vec{dl} = dx \hat{i}

Because x is the direction of the current flow.

As is said in the problem B is such that

\vec{B} = B \hat{j} = 0.62\hat{j} [ T]

so to use the equation above we first calculate the following cross product:

\vec{dl}\times\vec{B}=dx \hat{i}\times B \hat{j} = Bdx\hat{k}

so the force:

F = \int\limits^L_0 {i(\vec{dl}\times\vec{B})}=\int\limits^L_0{iBdx\hat{k}}

So here we use the fact that B=0 in any point of the x axis that is not x^{'}=0.27 [m], that means that we only need to do the integration between a very short distant behind the point x^{'}=0.27 [m] and a very short distant after that point, meaning:

\vec{F}= \lim_{h \to 0}{\int\limits^{x^{'}+h}_{x^{'}-h}{iBdx\hat{k}} }

so is the same as evaluating iBx at x=x^{'}

that is:

2,4 A * 0,62 T * 0,27 m \hat{k}

2,4 A * 0,62 (\frac{Kg}{A s^{2}}) * 0,27 m \hat{k}

2,4*0,62*2,7 ( \frac{ kgm }{ s^{2} } ) \hat{k}

\vec{F}=0.40176 N \hat{k}

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Answer:

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