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2 years ago

6

In an experiment, a ringing bell is placed in a vacuum jar that does not have any air in it. What best describes why the bell is

seen vibrating but not heard?

1 answer:

madam [21]2 years ago

3 0

Answer:

Light does not need a medium to travel travel through, but since waves must have a medium to vibrate, sound is not created where no air is present.

Explanation:

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Both atypical and traditional antipsychotics _____ levels of _____.

LiRa [457]

Answer:

Both atypical and traditional antipsychotics <u>blocks</u> levels of<u> </u><u>serotonin</u><u>.</u>

Explanation:

These drugs are capable of reducing or turning off positive psychotic symptoms such as hallucinations, delusions, and language and behavior disorder.

In addition to also acting as mood stabilizers, they have an impact on mania, depression, and produce low anxiety.

These anti-psychotics work on the 5-HT2A receptor, it belongs to the family of serotonin receptors and it is a G protein-coupled receptor. 5-HT is short for 5-hydroxy-tryptamine, the chemical name for serotonin.

This receptor became notorious for its importance as a target for drugs like LSD. Later it became important again due to the action of many antipsychotic drugs, especially atypical ones.

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3 years ago

A heliocentric system is _____-centered.<br><br> Milky Way<br> Earth<br> Moon<br> Sun

madreJ [45]

Answer: Sun

Explanation:

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3 years ago

Read 2 more answers

What is the answers

andriy [413]

Salt is a substance because a substance is a material that has constant composition regardless of its source. Salt is the only option that matches this description

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3 years ago

9. Una jeringa contiene cloro gaseoso, que ocupa un volumen de 95 mL a una presión de 0,96 atm. ¿Qué presión debemos ejercer en

masha68 [24]

Answer:

2.61 atm

Ley de Boyle

Explanation:

$P_1$ = Presión inicial = 0.96 atm

$P_2$ = Presión final

$V_1$ = Volumen inicial = 95 mL

$V_2$ = Volumen final = 35 mL

En este problema usaremos la ley de Boyle.

$\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow P_2=\dfrac{P_1V_1}{V_2}\\\Rightarrow P_2=\dfrac{0.96\times 95}{35}\\\Rightarrow P_1=2.61\ \text{atm}$

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.

4 0

2 years ago

oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student

12345 [234]

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

3 0

2 years ago