Aerobic cellular respiration have 3 parts, this is Glycolysis, Pyruvate Oxidation and Krebs cycle.
<h3>How is the aerobic breathing process?</h3>
Aerobic respiration consists of carrying out the process of degradation of organic molecules, reducing them to molecules with practically no releaseable energy. The products of the initial degradation of the organic molecule are combined with oxygen in the air and transformed into carbon dioxide and water.
In this case, Aerobic cellular respiration have 3 parts:
- Glycolysis(yeilds 2ATP & 2NADH).
- Pyruvate Oxidation(yeilds 2NADH).
- Krebs cycle(yeilds 2GTP,2FADH2 & 6NADH).
So the total =4ATPs (2GTP equivalent to 2ATP) +10NADH (equivalent to 30ATPs) + 2FADH2(4 ATPs) =38 ATPs.
See more about Aerobic cellular respiration at brainly.com/question/22531444
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1. the change in position of an object from start to finish, a vector quantity . . . . .<em> displacement</em>
2. a portion of space that contains a value for a measurable quantity at every point in space . . . . .<em> field </em>
3. speed = (distance) / <em>(time to cover the distance)</em>
4. the length of the entire path an object travels from start to finish . . . . . <em>distance</em>
5. a measurement that has both magnitude and direction . . . . . <em>vector</em>
6. a change in displacement with respect to time . . . . .<em> velocity</em>
7. a mental or physical construct or description that describes a physical phenomenon . . . . . <em>model</em>
8. a change in velocity with respect to time . . . . . <em>acceleration</em>
9. a measurement that only expresses magnitude, such as time, temperature, distance, and speed . . . . . <em>scalar</em>
10. objects that are thrown or launched in the air and are subject to gravity . . . . . <em>projectile</em>
Answer:
True The grid with more slits gives more angle separation increases
True. The grating with 10 slits produces better-defined (narrower) peaks
Explanation:
Such a system can be seen as a diffraction network in this case with different number of lines per unit length, the expression for the constructive interference of a diffraction network is
d sin θ = m λ
where d is the distance between slits or lines, m the order of diffraction and λ the wavelength.
For network with 5 slits
d = 1/5 = 0.2
For the network with 10 slits
d = 1/10 = 0.1
let's calculate the separation (teat) for each one
θ = sin⁻¹ (m λ / d)
for 5 slits
θ₅ = sin⁻¹ (m λ 5)
for 10 slits
θ₁₀ = sin⁻¹ (m λ 10)
we can appreciate that for more slits the angle increases
the intensity of a series of slits is
I = I₀ sin²2 (N d/2) / sin² d/2)
when there are more slits (N) the peaks have greater intensity and are more acute (half width decreases)
let's analyze the claims
False
True The grid with more slits gives more angle separation increases
False
True The expression for the intensity of the diffraction peaks the intensity of the peaks increases with the number of slits as well as their spectral width decreases
False
