For Q3, you can subsitute x = 2 and y = 5 into the systems
-5(2) + 5 = -5
so it's a solution for the first system
-4(2)+2(5) = 2
it's also a solution for the second system
So you have to add all the numbers to get the perimeter or the outside distance but it looks like t and s is there a few times so that’s were you have to simplify.
So here’s the answer simplified
4t+2s+w+v+x+u
Good luck!
<h3>Answer is -2</h3>
I hope it is helpful for you ....
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In terms of p, the answer is p= -q-3
