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vlada-n [284]
3 years ago
11

The two equal strong kids are having a tug a war. What do you expect to happen to the ball in this situation

Physics
1 answer:
borishaifa [10]3 years ago
3 0

Answer:as per as Newtons second law, The forces exerted on the rope create tension.

As such,The tension is equal to the applied force.The tension is trasmitted to the opposite side and of the rope delivering the applied force.

Hope this helps.. :)

You might be interested in
4. A net force of 15 N is exerted on a book to cause it to accelerate at a rate of 5 m/s2. Determine the mass of the
kenny6666 [7]

Answer:

<h2>3 kg </h2>

Explanation:

The mass of an object given it's force and acceleration can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{15}{5}  = 3 \\

We have the final answer as

<h3>3 kg</h3>

Hope this helps you

4 0
2 years ago
A 70 kg man's arm, including the hand, can be modeled as BIO 75-cm-long uniform rod with a mass of 3.5 kg. When the man raises b
Butoxors [25]

Answer:

  Δy = 7.1 cm

Explanation:

The center of mass of a body is defined

            y_{cm} = 1 /M ∑m_{i}  y_{i}i

Where M is the total mass of the body, m mass of each part and ‘y’ height

Let's apply this equation to our case

We locate the reference system on the shoulders

The height of the arms is at its midpoint

            y = -75/2 = 37.5 cm

With arms down

            y_{cm} = 1/70 (63 y₀ - 3.5 37.5 - 3.5 37.5)

            y_{cm} = 1/70 (63 y)₀ - 7 37.5)

With arms up

          y_{cm}’= 1/70 (63 y₀ + 3.5 y + 3.5 y)

          y_{cm}’= 1/70 (63y₀ + 7 35.5)

let's subtract the two equations

        y_{cm}’ - y_{cm} = 1/70 2 (7 35.5)

         Δy = y_{cm}’ - y_{cm} = 2 7 35.5 / 70

         ΔY = 7.1 cm

7 0
2 years ago
The speed of an object undergoing constant acceleration increased from 8.0 meters per second to 16.0 meters per second in 10. Se
saw5 [17]

v₀ = initial speed of the object = 8 meter/second

v = final speed of the object = 16 meter/second

t = time taken to increase the speed = 10 seconds

d = distance traveled by the object in the given time duration = ?

using the kinematics equation

d = (v + v₀) t/2

inserting the above values in the above equation

d = (16 + 8) (10)/2

d = 120 meter


6 0
3 years ago
A straight wire segment 5 m long makes an angle of 30° with a uniform magnetic field of 0.37 T. Find the magnitude of the force
SIZIF [17.4K]

Answer:

The magnitude of the force on the wire is 2.68 N.

Explanation:

Given that,

Length of the wire, L = 5 m

Magnetic field, B = 0.37 T

Angle between wire and the magnetic field, \theta=30^{\circ}

Current in the wire, I = 2.9 A

We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

F=BIL\ \sin\theta\\\\F=0.37\ T\times 2.9\ A\times 5\ m\times \ \sin(30)\\\\F=2.68\ N

So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.

7 0
3 years ago
Write the resistivity of gold, iron ,Mercury, silver,copper? which is bad conductor?​
Tamiku [17]

Answer:

Mercury is a bad conductor of heat but a fair conductor of electricity

By the way PURE SILVER is the best conductor of electricity

Please Mark as brainliest

3 0
2 years ago
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