Answer:
Explanation:
Let the force required be F . It is applied at the top of the box . The box is likely to turn about a corner . Torque of this force about this corner
= F x 2
This torque will try to turn the box . On the other hand the weight which is acting at CM will create a torque about the same corner . This torque will try to prevent the box to turn around the corner.
This torque of weight
= 100 x 1
= 100 pound ft.
For equilibrium
Torque of F = torque of weight.
F x 2 = 100
F = 50 pounds .
Explanation:
Efficiency is a way of describing the amount of useful output a process or machine can generate as a percentage of the input required to make it go. In other words, it compares how much energy is used to do work versus how much is lost or wasted to the environment. The more efficient the machine, the less energy wasted.
For example, if a heat engine is able to turn 75 percent of the fuel it receives into motion, while 25 percent is lost as heat in the process, it would be 75 percent efficient. Out of the original 100 percent of the fuel, 75 percent was output as useful work.
the equation:
energy efficiency =useful output energy/total input energy
Answer:
5m/s²
Explanation:
Given parameters:
Mass of wagon = 10kg
Force of pull = 70N
Frictional force = 20N
Unknown:
Acceleration of the wagon = ?
Solution:
Frictional force is a force that opposes motion.
The net force is given as:
Net force = mass x acceleration
Force of pull - Frictional force = mass x acceleration
Insert the parameters and solve;
70 - 20 = 10 x acceleration
50 = 10 x acceleration
Acceleration = 5m/s²
Mass x SH x °C (or K) ΔT
= 75g x 0.45J/g/K x 6.0 ΔT
= 202.5 Joules of heat absorbed.
(202.5J / 4.184J/cal = 48.4 calories).
I guess that is the answer
About 21c because it also depends on the weather outside
