This question is incomplete, the complete question is;
If the detailed experimentally determined calibration curve is;
Absorbance = 12,100 M⁻¹ × [ferroin (M)] + 0.00230
and the measured absorbance of a sample solution is 0.367, what is the ferroin concentration in the measured solution?
Choice of Answer
A) 2.76 x 10⁻⁵ M
B) 3.01 x 10⁻⁵ M
C) 3.45 x 10⁻⁵ M
D) none of the above
Answer:
the ferroin concentration in the measured solution is 3.01 × 10⁻⁵M
Option B) 3.01 x 10⁻⁵ M is the correct Answer
Explanation:
Given the data in the question;
Absorbance = 12,100 M⁻¹ × [ferroin (M)] + 0.00230 ------- let this be equation 1
Measured Absorbance = 0.367
so, we simply substitute value of measured absorbance into equation 1
0.367 = 12,100 × [ferroin] + 0.00230
solve for [ferroin ]
0.367 = 12,100 × [ferroin] + 0.00230
12,100 × [ferroin] = 0.367 - 0.00230
12,100 × [ferroin ] = 0.3647
[ferroin ] = 0.3647 / 12,100
[ferroin ] = 3.014 × 10⁻⁵ ≈ 3.01 × 10⁻⁵M
Therefore, the ferroin concentration in the measured solution is 3.01 × 10⁻⁵M
Option B) 3.01 x 10⁻⁵ M is the correct Answer
