Answer:
It's big brain time
Explanation:
Weathering is the process of breaking rocks into sediment while erosion is the process that wears away this sediment and other materials and moves them from one location to another. Agents of erosion include gravity, glaciers, wind, and water. Erosion only occurs when these agents have enough energy. The moment agents of erosion lose their energy and momentum they deposit their load. This process is known as deposition. The load is what the agent is carrying. As agents of weathering lose their energy, the heavier sediment is dropped. As the energy is lost, gravel, then sand, then silt, and then clay are deposited, due to their respective masses.
Mass movement, sometimes referred to as mass wasting, is what we call the movement of surface material due to gravity, water, wind, and ice. There are five main types of mass movements: falls, creep, flows, slides, and slump.
Answer:
A) 4 atoms/unit cell
B) 7.31 g/cm^3
Explanation:
A) Determine the number of atoms in each unit cell
attached below is the detailed solution
number of atoms per unit cell ( n ) = 4 atoms/unit cell
B) Given atomic weight of indium = 114.82 g/mol
hence the theoretical density = 7.31 g/cm^3
Attached below is a detailed solution of the question
To solve this item, we need write first all the necessary data to solve the problem. Governing principle of this problem is basically exponential decay of a certain substance.
Given:
Let t represents time
N represents mass of substance
Initially,
at t(0), N(0) = 190mg radioactive substance
at t(17), N(17) = 95mg radioactive substance
Required: N(21)
Solution:
We write first the formula for exponential decay, that is
N(t) = N(0)*e^(-k*t) ; k = exponential decay constant
We need first to determine the k, substituting the given we have
95 = 190*e^(-k*17)
Dividing by 190, we get
0.5 = e^(-k*17)
To eliminate the exponential e, we take the natural logs of both sides
ln(0.5) = ln(e^(-k*17))
-0.693 = -k*17
Solving for k,
k = 0.04077
To solve for N(21), we need to substitute k to the original equation
N(21) = N(0)e^(-k*21)
N(21) = 190*e^(-0.04077*21)
N(21) = 80.7 mg
<em>ANSWER: 80.7 mg radioactive substance left after 21 hours </em>
The balloon grows because of the oxygen build up.