Answer:
11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Explanation:
Chloroacetic acid is an monoprotic acid.
Neutralization reaction: 
So, 1 mol of chloroacetic acid is neutralized by 1 mol of NaOH.
Molar mass of chloroacetic acid = 94.5 g/mol
So, 0.154 g of chloroacetic acid =
moles of chloroacetic acid
= 0.00163 moles of chloroacetic acid
Lets assume V mL of 0.1400 M of NaOH is required to reach equivalence point.
So, number of moles of NaOH needed to reach equivalence point
=
moles
So, 
or, V = 11.6
Hence, 11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.
Answer : The pH of a 0.1 M phosphate buffer is, 6.86
Explanation : Given,

Concentration of acid = 0.1 M
Concentration of conjugate base (salt) = 0.1 M
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:


Therefore, the pH of a 0.1 M phosphate buffer is, 6.86
Answer: unused waste from food processing
Explanation: have you takin the chemical reaction system unit test yet? It’s alternated