Answer:
The pieces will attract one another
Explanation:
From the law of conservation of energy, we know that energy can neither be created nor destroyed, but transformed. If one piece of the toy that was neutral ends up having an electric charge (positive or negative), from the conservation of energy, the other piece must have a charge opposite to that on the other charged piece but equal in magnitude. These two pieces which are oppositely charged attracts each other, this shows that electric charge is conserved.
Answer:
The conductivity of Nichrome is 
.
Explanation:
Given:
Potential difference (V) = 2.0 V
Current flowing (I) = 4.0 A
Length of wire (L) = 1.0 m
Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]
We know, from Ohm's law, that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. Therefore, the resistance of the nichrome wire is given as:
Now, resistance of the nichrome wire in terms of its resistivity, length and area of cross section is given as:
Where, 
Now, plug in all the values given and solve for 
. This gives,
Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:
Conductivity is measured in Siemens per meter (S/m)
Therefore, the conductivity of Nichrome is .
I believe the red light would go faster than the blue.
Answer:
The gravitational potential energy the barbells have at the maximum height, is P.E. = 3680·h J = 1.10 × 10⁴ units
Where;
h = The maximum height to which he lifts the barbells
Explanation:
The given parameters are;
The amount of work done by the championship lifter in lifting the weight, W = 1.10 × 10⁴ units
The weight of the barbells lifted by the championship lifter, N = 3680 N
The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;
P.E. = m × g × h
Where;
m = The mass of the barbells;
g = The acceleration due to gravity = 9.8 m/s²
h = The maximum height to which the barbells are lifted by the championship weight lifter
m × g = The weight of the barbells = 3680 N
∴ P.E. = 3680 N × h = 3680·h J
By the conservation of energy principle, work done by the championship weight lifter = The maximum gravitational potential energy gained by the barbell = The gravitational potential energy at the maximum height, P.E.
∴ The gravitational potential energy the barbells have at the maximum height, P.E. = 3680·h J = W = 1.10 × 10⁴ units
