The word displacement implies that an object has moved, or has been displaced. Displacement is defined to be the change in position of an object.
Displacement is defined as the act of moving someone or something from one position to another or the measurement of the volume replaced by something else
Answer:
The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.
Explanation:
From coulomb's law, F = Eq
Thus,
F = E₁q₁
F = E₂q₂
Then
E₂q₂ = E₁q₁

where;
E₂ is the external electric field due to second test charge = ?
E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C
q₁ is the first test charge = 13 mC
q₂ is the second test charge = 23 mC
Substitute in these values in the equation above and calculate E₂.

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.
However, the direction of the external field is still to the right.
<span>The metric
system is the oldest name for the international system of units. The answer is <u>a.
True. </u>SI unit or the international systems of units are based on seven
basic units; the meter, kilogram, second, ampere, Kelvin, candela and mole. All
of these basic units are divided into multiples by a power of ten. For example
in meters, 1 meter is equal to: 1000 millimeter, 100 centimeter, 10 decimeter,
0.1 decameter, 0.01 hectometer, 0.001 kilometer and so on and so forth.</span>
<u>Answer:</u>
The ball is rolling at a speed of 0.02 meter per second.
<u>Step by step explanation:</u>
We are given that there is a 800 gram bowling ball rolling in a straight line. If its momentum is given to be 16 kg.m/sec, we are to find its velocity.
For this, we will use the formula of momentum.
<em>Momentum = mass × velocity</em>
16 = 800 × velocity
Velocity = 16/800 = 0.02 meter per second
Answer:
y = 2.74 m
Explanation:
The linear thermal expansion processes are described by the expression
ΔL = α L ΔT
Where α the thermal dilation constant for concrete is 12 10⁻⁶ºC⁻¹, ΔL is the length variation and ΔT the temperature variation in this case 20ªc
If the bridge is 250 m long and is covered by two sections each of them must be L = 125 m, let's calculate the variation in length
ΔL = 12 10⁻⁶ 125 20
ΔL = 3.0 10⁻² m
Let's use trigonometry to find the height
The hypotenuse Lf = 125 + 0.03 = 125.03 m
Adjacent leg L₀ = 125 m
cos θ = L₀ / Lf
θ = cos⁻¹ (L₀ / Lf)
θ = cos⁻¹ (125 / 125.03)
θ = 1,255º
We calculate the height
tan 1,255 = y / x
y = x tan 1,255
y = 125 tan 1,255
y = 2.74 m