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BabaBlast [244]
3 years ago
15

Which of the following is best determined by applying the principles of relativity and uncertainty rather than Newtonian physics

?
A.the velocity of a satellite

B.the speed of an object moving at close to the speed of light

C.the length of an accelerating race car

D.the momentum of a plane
Physics
2 answers:
kodGreya [7K]3 years ago
5 0

Answer:

momentum of an electron

Explanation:

antoniya [11.8K]3 years ago
3 0
It’s probably a it’s the only one that sounds right
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A 95.0kg weightlifter pushes on a 800,000 kg wall for 400s but it does not move. How much work does he do on the wall?
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<span>The weightlifter does no work. Although he has exerted force, work is the product of force over distance. Since he has not moved the wall he has done no work.</span>
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4 years ago
Zero field spot for opposite unequal charges
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Answer:

The zero field location has to be on the line running between the two point charges because that's the only place where the field vectors could point in exactly opposite directions. It can't be between the two opposite charges because there the field vectors from both charges point toward the negative charge.

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3 years ago
% = Wo/Wi x 100 Solve for Wo<br> % = Wo/Wi x 100 Solve for Wi
irga5000 [103]
1) % = (Wo /Wi) * 100

Solve for Wo => Wo = (% / 100) * Wi

For example, % =30% and Wi = 250 => Wo = (30 /100) * 250 = 0.30 * 250 = 75

Wo = 75

2) % = (Wo / Wi) * 100

Solve for Wi

=> Wi = Wo * (%/100)

For example, Wo = 125 and % = 40%

=> Wi = 125 * (40 / 100) = 125 * 0.40 = 50

Wi = 50
8 0
3 years ago
The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample
Bond [772]

Answer:

4276.98 years

Explanation:

t = age of the sample in numbers of years

T = half life of the carbon-14 isotope = 5730 yrs

λ = decay constant of carbon-14

decay constant is given as

\lambda =\frac{0.693}{T}

\lambda =\frac{0.693}{5730}

\lambda = 0.000121

A₀ = activity of Carbon-14 in living plants

A  = activity of Carbon-14 after time "t" = (0.596) A₀

Using the equation

A = A_{o} e^{-\lambda t}

(0.596) A₀  = A_{o} e^{-0.000121 t}

0.596 = e^{-0.000121 t}

t = 4276.98 years

4 0
3 years ago
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