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BabaBlast [244]
3 years ago
15

Which of the following is best determined by applying the principles of relativity and uncertainty rather than Newtonian physics

?
A.the velocity of a satellite

B.the speed of an object moving at close to the speed of light

C.the length of an accelerating race car

D.the momentum of a plane
Physics
2 answers:
kodGreya [7K]3 years ago
5 0

Answer:

momentum of an electron

Explanation:

antoniya [11.8K]3 years ago
3 0
It’s probably a it’s the only one that sounds right
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What is E(r)E(r)E(r), the radial component of the electric field between the rod and cylindrical shell as a function of the dist
andriy [413]

Answer:

E(r) = λ/2πrε0

Explanation:

If we consider an infinitely long line of charge with the charge per unit length being λ, we can take advantage of the cylindrical symmetry of this situation.

By symmetry, i mean that the electric fields all point radially away from the line of charge and thus there is no component parallel to the line of charge.

Niw, let's use a cylinder (with an arbitrary radius (r) and length (l)) centred on the line of charge as our Gaussian surface.

Doing that will mean that the electric field would be perpendicular to the curved surface of the cylinder. Therefore, the angle between the electric field and area vector is equal to zero and cos θ = cos 0 = 1

Now, the top and bottom surfaces of the cylinder will lie parallel to the electric field. Therefore, the angle between the area vector and the electric field would be 90° and cos θ = cos 90 = 0

Now, we know that according to Gauss Law,

Electric Flux, Φ = E•dA

Thus,

Total Φ = Φ_curved + Φ_top + Φ_bottom

Thus,

Φ = ∫E•dA cos 0 + ∫E•dA cos 90° + ∫E•dA cos 90°

We now have ;

Φ = ∫E . dA × 1

Since we are dealing with the radial component, the curved surface would be equidistant from the line of charge and the electric field in the surface will be the same magnitude throughout.

Thus,

Φ = ∫E•dA = E∫dA = E•2πrl

The net charge enclosed by the surface is given by:

q_net = λl

So using gauss theorem, we have;

Φ = E•2πrl = q_net/εo = λl/εo

E•2πrl = λl/ε0

Making E the subject, we obtain ;

E = λ/2πrε0

4 0
3 years ago
How is a crowbar used to remove the top of a box change the direction of the force
Lemur [1.5K]
The crowbar is placed under a small edge under the top of the box. The crowbar will send the box lid flying from the opposite direction that the crowbar is placed. Please give Brainlest if you understand.
7 0
3 years ago
In a series circuit what effect will adding more resistors to the circuit have
zhuklara [117]

Answer:In a series circuit, adding more resistors increases total resistance and thus lowers current. But the opposite is true in a parallel circuit because adding more resistors in parallel creates more choices and lowers total resistance. If the same battery is connected to the resistors, current will increase.

Explanation:

8 0
3 years ago
A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer
dlinn [17]
<h2>Answer:7.14ms^{-1},4.125ms^{-1}</h2>

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let v be the total velocity.

Given that,v=8.25ms^{-1}

We call the horizontal velocity as v_{h} and the vertical velocity as v_{v}.

v_{h}=vCos\alpha

v_{v}=vSin\alpha

where \alpha is the angle between the object and horizontal.

It is given that \alpha =30^{0}

v_{h}=8.25\times Cos(30^{0})=7.14ms^{-1}

v_{v}=8.25\times Sin(30^{0})=4.125ms^{-1}

7 0
3 years ago
What do measurements of the number of neutrinos emitted by the Sun tell us about conditions deep in the solar interior?
OverLord2011 [107]

Answer:

The neutrinos are produced in the core of the sun by nuclear fusion and measuring their number helps us confirm that there are enough proton-proton chain reactions of each which produce a neutrino and going on in the Sun's core to explain the energy output of the Sun.

4 0
3 years ago
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