The largest energy release will take place when the electron jumps between the greatest number of levels. In this case from infinity down to 2
This is the emitted photon with the most energy ( in the Balmer series), the highest frequency and therefore the shortest wavelength.
Balmer's original formula was
Wavelength = 3645.6 . 10^–10 ( n^2 / (n^2 – 4) )
When n => infinity
Wavelength = 3.6456 . 10^–7 m ( or 364.5 nm)
Answer:
0.7246 M
Explanation:
Considering:
Or,
Given :
For
:
Molarity = 2.086 M
Volume = 188.9 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 188.9×10⁻³ L
Thus, moles of
:
Moles of
= 0.39405 moles
For NaOH :
Molarity = 0.4607 M
Volume = 269.3 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 269.3×10⁻³ L
Thus, moles of NaOH :
Moles of NaOH = 0.1241 moles
According to the given reaction:
1 moles of
react with 2 moles of NaOH to form 1 mole of sodium sulfate.
Thus,
2 moles of NaOH react with 1 mole of 
1 mole of NaOH react with 1/2 mole of 
0.1241 moles of NaOH react with (1/2)×0.1241 mole of 
Moles of
that got reacted = 0.06205 moles
Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles
Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L
Concentration of
:
<u>Concentration of
= 0.7246 M</u>
Answer:
Explanation: Q1 = mc(ice) ΔT (ice warms)
Q2 = ms (ice melts)
Q3 = mc((water) ΔT (water warms)
Q4 = mr (water boils)
Q5 = mc(vapour)ΔT
There are 4 moles of (aq) showed in the reaction i think