Answer:
The answer to your question is below
Explanation:
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Answer:
The volume of hydrogen gas generated by given reaction is 9.48 L
Explanation:
Firstly, we calculate the mole of Zinc added, n = 25.5 / 65 = 0.392 mol
With the same equivalent, the mole of generated hydrogen gas will be the same, at 0.392 mol.
Secondly, we get the equation
<em>P . V = n . R . T</em>
with P (pressure, atm), V (volume, litre), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)
So we have to convert the given information to correct unit
P = 742 mmHg = 0.976 atm
T = 15 °C = 288 K
Hence we can calculate the generated volume by
V = n . R . T / P = 0.392 x 0.082 x 288 / 0.976 = 9.48 L
Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.
Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O
It is a very large seamount and island created by hot-spot volcanism
Supercooling<span>, a state where liquids do not solidify even below their normal freezing point. Means sometimes we have liquid water below 0 degree C.</span>
