Answer:
Kp is 0.228/atm
Explanation:
This is the reaction:
CO + Cl<u>₂</u> → CCl₂O
1 mol of carbon monoxide and 1 mol of chlorine produce 1 mol of phosgene.
Formula for Kp which derivates from Kc is:
Kp = Kc (R.T)ⁿᵇ ⁻ ⁿᵃ
Δп = nb (moles in the products) - nₐ(moles in the reactants)
Δп = 1 - 2 = -1
T is T° in K → T°C + 273 = 611°C +273 = 884K
R → Universal constant gas → 0.082 L.atm/mol.K
We replace the data: Kp = 16.5 L/mol (0.082 . 884K)⁻¹ → 0.228/atm
Density = mass / volume
1.5 = m / 50.0
m = 1.5 x 50.0
m = 75 g
hope this helps!
Answer:
molarity = 0.385 moles/kg
Explanation:
Assume that the volume of the aqueous solution given is 1 liter = 1000 ml
Now, density can be calculated using the following rule:
density = mass / volume
Therefore:
mass = density * volume = 1.23 * 1000 = 1230 grams
Now, 0.467 m/L * 1L = 0.467 moles of HCl
We will get the mass of the 0.467 moles of HCl as follows:
mass = molar mass * number of moles = (1+35.5)*0.467 = 17.0455 grams
Now, we have the mass of the solution (water + HCl) calculated as 1230 grams and the mass of the HCl calculated as 17.0455 grams. We can use this information to get the mass of water as follows:
mass of water = 1230 - 17.0455 = 1212.9545 grams
Finally, we will get the molarity as follows:
molarity = number of moles of solute / kg of solution
molarity = (0.467) / (1212.9594*10^-3)
molarity = 0.385 mole/kg
Hope this helps :)
Answer:
The % yield is 56.6 %
Explanation:
This is the reaction:
C₂H₄ + Cl₂ → C₂H₄Cl₂
Molar mass of ethylene gas: 28 g/m
Mol = mass / molar mass
140 g / 28 g/m = 5 moles
Ratio is 1:1, so 5 moles of ethylene produce 5 moles of dichloro ethane.
Molar mass of C₂H₄Cl₂ = 98.9 g/m
Mass of C₂H₄Cl₂ produced = 98.9 g/m . 5 m → 494.5 g
% yield reaction
(280 g / 494.5 g ) . 100 = 56.6%
Answer:
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