1. 3A + 2B + C + 2D + 20 kJ
1 answer:
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the reaction is
HCl (aq) + NaOH (aq) -> NaCl (aq) + H2O (l).
the enthalpy of reaction is H=-54 kJ
Which means that one mole of HCl reacts with one mole of NaOH and gives 54 kJ of energy / heat
The reaction is exothermic and the graph will be like as shown in figure (1)
The question is
What is the enthalpy change if 10 mL HCl 1 M is reacted with 20 mL 1 M NaOH?
Moles of HCl = molarity X volume = 1 M X 10 mL = 10 mmoles
moles of NaOH reacted = moles of NaOH
so total moles of acid base reacted = 10mmoles = water formed
when one mole of acid base reacted to give one mole of H2O
so when 10mmole of water are formed energy released is = 54 X 10 X 10^-3 = 0.54 kJ
reaksinya
HCl (aq) + NaOH (aq) -> NaCl (aq) + H2O (l).
entalpi reaksi adalah H = -54 kJ
Yang berarti satu mol HCl bereaksi dengan satu mol NaOH dan memberikan 54 kJ energi / panas
Reaksinya eksotermik dan grafiknya akan seperti yang ditunjukkan pada gambar (1)
Pertanyaannya adalah
Apa perubahan entalpi jika 10 mL HCl 1 M direaksikan dengan 20 mL 1 M NaOH?
Moles HCl = molaritas X volume = 1 M X 10 mL = 10 mmoles
Tahi lalat NaOH bereaksi = mol NaOH
sehingga jumlah mol asam basa bereaksi = 10mmol = air terbentuk
ketika satu mol asam basa bereaksi untuk memberikan satu mol H2O
jadi ketika 10mmole air terbentuk, energi yang dilepaskan adalah = 54 X 10 X 10 ^ -3 = 0,54 kJ
