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Nikitich [7]
3 years ago
14

How to balance _h2s+ _o2 = _h2o+ _s

Chemistry
1 answer:
goldfiish [28.3K]3 years ago
5 0

Answer:

<u>2</u>H₂S + <u>1</u>O₂ → <u>2</u>H₂O + <u>2</u>S

Explanation:

<u>SOLUTION :-</u>

Balance it by using 'hit & trial' method , and you'll get the answer :-

<u>2</u>H₂S + <u>1</u>O₂ → <u>2</u>H₂O + <u>2</u>S

<u></u>

<u>VERIFICATION :-</u>

<em>In reactant side of equation :-</em>

  • Number of atoms in H = 2×2 = 4
  • Number of atoms in S = 2×1 = 2
  • Number of atoms in O = 1×2 = 2

<em>In product side of equation :-</em>

  • Number of atoms in H = 2×2 = 4
  • Number of atoms in O = 2×1 = 2
  • Number of atoms in S = 2×1 = 2

Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.

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5 0
3 years ago
How is oxygen different than neon explain your answer
lora16 [44]
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5 0
3 years ago
What is the molarity of a 17.0% by mass solution of sodium acetate, NaC2H3O2 (82.0 g/mol), in water? The density of the solution
sattari [20]

Answer:

[NaCH₃COO] = 2.26M

Explanation:

17% by mass is a sort of concentration. Gives the information about grams of solute in 100 g of solution. (In this case, 17 g of NaCH₃COO)

Let's determine the volume of solution, by density

Mass of solution / Volume of solution = Solution density

100 g / Volume of solution = 1.09 g/mL

100 g / 1.09 g/mL = 91.7 mL

17 grams of solute is contained in 91.7 mL

Molarity (M) = Mol of solute /L of solution

91.7 mL / 1000 = 0.0917L

17 g / 82 g/m = 0.207 moles

Molariy = 0.207 moles / 0.0917L → 2.26M

4 0
3 years ago
Serine has pka1 = 2.21 and pka2 = 9.15. use the henderson-hasselbalch equation to calculate the ratio neutral form/protonated fo
malfutka [58]
Calculate the ratio by using Henderson-Hasselbalch equation:

pH = pKa + log [neutral form] / Protonated form

3.05 = 2.21 + log [neutral form] / [Protonated form]

3.05 - 2.21 = log [neutral form] / [Protonated form]

0.84 = log [neutral form] / [Protonated form]

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8 0
4 years ago
A compound is 80.0% carbon and 20.0% hydrogen by mass. assume you have a 100.-g sample of this compound. the molar mass of the c
ch4aika [34]
Basis of the calculation: 100g
 
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 Mass of carbon = (100 g)(0.80) = 80 g
  Number of moles of carbon = (80 g)(1 mole / 12g) = 20/3

For Hydrogen:
  Mass of hydrogen = (100 g)(0.20) = 20 g
     Number of moles of hydrogen = (20 g)(1 mole / 1 g) = 20

Translating the answer to the formula of the substance,
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Dividing the answer,
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The molar mass of the empirical formula is:
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Since, the molar mass given for the molecular formula is 30.069 g/mol, the molecular equation is,
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ANSWER: C2H6

 
4 0
4 years ago
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