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3 years ago

15

What do melting, evaporation, and sublimation have in common?

1 answer:

kvv77 [185]3 years ago

8 0

Explanation:

Sublimation describes a solid turning directly into a gas. Melting, on the other hand, occurs when a solid turns into a liquid. Water can, under the right circumstances, sublimate, though it usually melts at temperatures above 0 degrees Celsius or 32 degrees Fahrenheit. Carbon dioxide (CO2), however, is very different. The conditions that determine whether CO2 melts or sublimates are both temperature and atmospheric pressure.

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Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.25 M lactic acid and 40.0 mL of 0.75 M sodium lactate. (Th

Naya [18.7K]

Answer:

pH = 3.37

Explanation:

A weak acid as lactic acid in a solution with sodium lactate (Its conjugate base) produce a buffer. The pH of this buffer is obtained using H-H equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer,</em>

<em>pKa is 3.86</em>

<em>And [] could be taken as the moles of A- = Sodium lactate and HA = Lactic acid.</em>

<em />

Moles A-:

40.0mL = 0.0400L * (0.75mol / L) = 0.030 moles A-

Moles HA:

75.0mL = 0.0750L * (1.25mol / L) = 0.09375 moles HA

Replacing:

pH = 3.86+ log [0.030 moles A-] / [0.09375 moles HA]

<h3>pH = 3.37</h3>

<em />

7 0

3 years ago

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide (ki) reacts with 50.00 ml of sulfuric acid solut

g100num [7]

Answer: 0.19M

Explanation: $2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O$

Using Molarity equation:

$n_1M_1V_1=n_2M_2V_2$

$M_1$ = molarity of acid

$V_1$ = volume of acid

$M_2$ = molarity of base

$V_2$ = volume of base

$2\times M_1\times 50ml=1\times 0.500M\times 38.74ml$

$M_1=0.19M$

Thus the concentration of the $H_2SO_4$ solution is 0.19M.

6 0

3 years ago

Read 2 more answers

If a sample of 4 moles of gas has a pressure of 567.42 kPa and a volume of 12.0 L, what is it's temperature?

Lady_Fox [76]

Your answer is b, hope this helps ;)

7 0

3 years ago

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What qualities can be used to identify binary covalent compounds?

alexandr402 [8]

Either covalent compounds are neutral, covalent compounds share electrons

3 0

4 years ago