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Nat2105 [25]
3 years ago
5

How many edges and vertices does the figure shown have?

Mathematics
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer:

B.15 edges and 10 vertices

Step-by-step explanation:

took test on Time4Learning:)

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Eva8 [605]

Answer:

5100 cans

Step-by-step explanation:

1470 L = 1,470,000 ml

1,470,000/288.2 (per can) = 5100.62456627

round DOWN because we want full cans and you get 5100 cans

4 0
3 years ago
On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the ret
Nikolay [14]

Answer:

B on edu2020

Step-by-step explanation:

4 0
3 years ago
A student writes the difference between 15 and the product of 5 and y to describe the expression 5y negative 15
mezya [45]
The difference means subtract
5y means product or 5 times y
5y - 15
4 0
3 years ago
Fastest one to answer gets 11 points and marked as brainiest! answer ASAP
MAVERICK [17]

Answer:

0.24 its opposite value is - 0.24

1/4 its opposite value is -1/4

0

-5 its opposite value is 5

240 which is positive and its opposite value is -240

Step-by-step explanation:

hey

from the given statement we can see that question demand is about the opposite values. so

as our first value is 0.24 its opposite value is - 0.24

then move on next value is 1/4

its opposite value is -1/4

0 is a neutral value it neither positive or negative

move on to the next value which is -5 who is already negative

so we take a positive value that is 5

again move to 240 which is positive and its opposite value is -240

Hope it will be brainliest to you

5 0
3 years ago
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
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