Substance: Specific Heat (C) in joules per gram/degrees centigrade:
Water (ice) 2.05
Iron 0.46
Aluminium 0.90
Gold 0.13
Copper 0.39
Ammonia (liquid) 4.70
Ethanol 2.44
Gasoline 2.22
Water (liquid) 4.18
Water (vapor) 2.08
Air (25 degrees Celsius) 1.01
Oxygen 0.92
Hydrogen 14.30
To know that we clear the equation q=m*C*Δt for the specific heat (C) and solve the equation. Keep in mind that we need to use the heat (520 J) in Joules since the values from the question and the table are in Joules.
q/m∗ΔT = C = 520J/200g∗(45degC−25degC) =
0.13J/gdegC
As you can see, the substance that has this specific heat is GOLD.
2C₆H₁₄+19O₂⇒14H₂O+12CO₂+energy You can tell that the energy is on the left side since the reactoin is highly exothermic meaning it releases heat which can also be thought of as energy.
