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never [62]
3 years ago
11

A 200 g block of a substance requires 520 J of heat to raise its temperature from 25°C to 45°C.

Chemistry
1 answer:
harkovskaia [24]3 years ago
6 0

<h3>Answer: </h3>

The answer is gold.

<h3>Explanation:</h3>

Substance: Specific Heat (C) in joules per gram/degrees centigrade:

Water (ice) 2.05

Iron 0.46

Aluminium 0.90

Gold 0.13

Copper 0.39

Ammonia (liquid) 4.70

Ethanol 2.44

Gasoline 2.22

Water (liquid) 4.18

Water (vapor) 2.08

Air (25 degrees Celsius) 1.01

Oxygen 0.92

Hydrogen 14.30

To know that we clear the equation q=m*C*Δt for the specific heat (C) and solve the equation. Keep in mind that we need to use the heat (520 J) in Joules since the values from the question and the table are in Joules.

q/m∗ΔT = C = 520J/200g∗(45degC−25degC) =

0.13J/gdegC

As you can see, the substance that has this specific heat is GOLD.

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Answer:

1) 2.054 x 10⁻⁴ mol/L.

2) Decreasing the temperature will increase the solubilty of O₂ gas in water.

Explanation:

1) The solubility of O₂ gas in water:

  • We cam calculate the solubility of O₂ in water using Henry's law: <em>Cgas = K P</em>,
  • where, Cgas is the solubility if gas,
  • K is henry's law constant (K for O₂ at 25 ̊C is 1.3 x 10⁻³ mol/l atm),
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2) The effect of decreasing temperature on the solubility O₂ gas in water:

  • Decreasing the temperature will increase the solubilty of O₂ gas in water.
  • When the temperature increases, the solubility of O₂ gas in water will decrease because the increase in T will increase the kinetic energy of gas particles and increase its motion that will break intermolecular bonds and escape from solution.
  • Decreasing the temperature will increase the solubility of O₂ gas in water will because the kinetic energy of gas particles will decrease and limit its motion that can not break the intermolecular bonds and increase the solubility of O₂ gas.


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Element X consist of two isotopes with masses of 62.9 and 64.9. The relative atomic mass of the element is 63.6. What is th
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it is 50%

Explanation:

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64.9x50=3245

3245+3145=6390

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Rutherford in his gold foil experiment revised the plum pudding model of the atom;

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