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kvv77 [185]
2 years ago
10

Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflec

tion is the angle between the reflected ray and the normal, which is the surface of the mirror. Which statement corrects an error on the site? The normal is a line perpendicular to the surface of the mirror. The normal is a line perpendicular to the incoming ray. The angle of reflection is the angle between the incoming ray and the normal. The angle of reflection is the angle between the reflected ray and the incoming ray.
Physics
2 answers:
tatiyna2 years ago
5 0

'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

Hence 'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site

To learn more about the law of reflection refer to the link;

brainly.com/question/12029226

juin [17]2 years ago
4 0

Answer:

A

Explanation:

I took the test

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3 years ago
Say I have a series circuit with 20v and four 65 ohm resistors, what is the current in each resistor?
Komok [63]
Data:

E = 20 V
R_{1} = 65\Omega
R_{2} = 65\Omega
R_{3} = 65\Omega
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<span>Now that we have all the values ​​we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:

</span>R_{T} =  R_{1} + R_{2} + R_{3} + R_{4}
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<span>Like this:
</span>
I_{T} =  \frac{E}{ R_{T} }

I_{T} = \frac{20}{ 260 }
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\boxed{\boxed{I_{T} \approx 0,07A}} 
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