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kolezko [41]
3 years ago
5

What kinds of sacrifices do governments face when considering how to reduce greenhouse gases ?

Chemistry
2 answers:
Helga [31]3 years ago
7 0
People might get mad at them and it might cost a lot more money
guapka [62]3 years ago
5 0

Answer:

m risus ante, dapibus a ipsum dolor sit amet, add cream or a great slaughter. Fusce dui lectus, laoreet congue vel, it was said of life in hatred. Until the bananas. Lorem ipsum dolor sit amet, consectetur adipiscing elit. In fact, lacinia pulvinar dolor libero facilisis. Nutrition protein produced et. In fact, risus ante, dapibus a ipsum dolor sit amet, add cream or a great slaughter. Fusce dui lectus, laoreet congue vel, it was said of life in hatred. Until the bananas. Lorem ipsum deceit

Explanation:

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What is the noble gas electron configuration for an electrically neutral atom of sulfur
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S=  [Ne] 3s²3p⁴

S2- = [Ne] 3s²3p6 = [Ar]


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Tari serampang dua belas berasal dari​
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The storage and transport of material takes place in the ________.
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The blank is - <span>Endoplasmic reticulum</span>
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What is the organic molecule
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2 years ago
Read 2 more answers
The combustion of 0.590 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
Alenkinab [10]

Answer:

2.943 °C temperature change from the combustion of the glucose has been taken place.

Explanation:

Heat released on combustion of Benzoic acid; :

Enthaply of combustion of benzoic acid = 3,228 kJ/mol  

Mass of benzoic acid = 0.590 g

Moles of benzoic acid = \frac{0.590 g}{122.12 g/mol}=0.004831 mol

Energy released by 0.004831 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004831 mol=15.5955 kJ=15,595.5 J

Heat capacity of the calorimeter = C  

Change in temperature of the calorimeter = ΔT = 2.125°C

Q=C\times \Delta T

15,595.5 J=C\times 2.125^oC

C=7,339.05 J/^oC

Heat released on combustion of Glucose: :

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=1.400 g

Moles of glucose =\frac{1.400 g}{180.16 g/mol}=0.007771 mol

Energy released by the 0.007771 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.007771 mol=21.6030 kJ=21,603.01 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

21,603.01 J=7,339.05 J/^oC\times \Delta T'

\Delta T'=2.943^oC

2.943 °C temperature change from the combustion of the glucose has been taken place.

8 0
3 years ago
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