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4 years ago

What is a main difference between a mixture and a pure substance?

2 answers:

5 0

A mixture can vary in composition, but a pure substance cannot. think of salad dressing in a bottle and then think of pure water.

alex41 [277]4 years ago

4 0

The answer is to this question is D

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What scientist do that is the basis for their investigation

Tju [1.3M]

They come up with a hypothesis (question to investigate), then they work out what variables and what they will be measuring, keeping the same and changing in the experiment

4 0

3 years ago

Read 2 more answers

A slice of Swiss cheese contains 41 mg of sodium.

larisa86 [58]

Answer:

a. 41 mg equals 0.041 grams.

b. 41 mg equals 0.0014462 ounces

c. 41 mg equals 9.039*10⁻⁵ pounds

Explanation:

You know that a slice of Swiss cheese contains 41 mg of sodium.

a. What is this mass in grams?

Knowing that 1 mg = 10⁻³ g, you can apply the following rule of three: if 1 mg equals 10⁻³ g or 0.001 grams, 41 mg will be equivalent to how much mass in g?

$mass=\frac{41 mg*0.001 g}{1 mg}$

mass= 0.041 grams

41 mg equals 0.041 grams.

b. What is this mass in ounces?

Knowing that 1 mg = 3.5274 * 10⁻⁵ ounces, you can apply the following rule of three: if 1 mg equals 3.5274 * 10⁻⁵ ounces, 41 mg will be equivalent to how much mass in ounces?

$mass=\frac{41 mg*3.5274*10^{-5}ounces }{1 mg}$

mass= 1.4462*10 ⁻³ ounces= 0.0014462 ounces

41 mg equals 0.0014462 ounces

c. What is this mass in pounds?

Knowing that 1 mg = 2.20462 * 10⁻⁶ pounds, you can apply the following rule of three: if 1 mg equals 2.20462 * 10⁻⁶ pounds, 41 mg will be equivalent to how much mass in pounds?

$mass=\frac{41 mg*2.20462*10^{-6}pounds }{1 mg}$

mass= 9.039*10⁻⁵ pounds

41 mg equals 9.039*10⁻⁵ pounds

5 0

3 years ago

What gas is the product of propane burning

GaryK [48]

I believe propane burns to form water vapor and carbon dioxide

4 0

4 years ago

A solution is prepared by mixing 525 mL of ethanol with 597 mL of water. The molarity of ethanol in the resulting solution is 8.

Alenkinab [10]

Answer:

$\Delta V = 234.736\,mL$

Explanation:

The quantity of moles of ethanol in the solution is:

$n_{C_{2}H_{5}OH} = \left(\frac{597\,mL}{1000\,mL} \right)\cdot \left(8.35\,\frac{mol}{L} \right)$

$n_{C_{2}H_{5}OH} = 4.985\,mol$

The mass and volume of ethanol in the solution are, respectively:

$m_{C_{2}H_{5}OH} = (4.985\,mol)\cdot \left(46.07\,\frac{g}{mol} \right)$

$m_{C_{2}H_{5}OH} = 229.658\,g$

$V_{C_{2}H_{5}OH} = \frac{229.658\,g}{0.7893\,\frac{g}{mL} }$

$V_{C_{2}H_{5}OH} = 290.964\,mL$

The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:

$\Delta V = (525\,mL+597\,mL) - (597\,mL + 290.964\,mL)$

$\Delta V = 234.736\,mL$

8 0

3 years ago

A fatty acid consists of -COOH bonded to a long chain of:

Sophie [7]

The -COOH is bonded to a long chain of hydrocarbons in a fatty acid.

A hydrocarbon chain is comprised of both carbon (C) and hydrogen (H) atoms. The 'acid' part is made up of the -COOH portion, whereas the 'fatty' part is made up of the long hydrocarbon chain that it is attached to.

7 0

3 years ago

Read 2 more answers