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2 years ago

Help me out brothas

Mathematics

1 answer:

Jobisdone [24]2 years ago

4 0

$C = \frac{5}{9} (f - 32)$

$c=\frac{5(f-32)}{9}$

c×9=5(f−32)

9c=5(f−32)

$\frac{9c}{5}=f-32$

$\frac{9c}{5}+32=f$

$f=\frac{9c}{5}+32$

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Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

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3 years ago

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Square root:27 + SR:48+SQ:12 = ???

Anika [276]

Sqrt(27)+sqrt(48)+sqrt(12)
Sqrt(27)=sqrt(3*3*3)=3*sqrt(3)
Sqrt(48)=sqrt(4*4*3)=4*sqrt(3)
Sqrt(12)=sqrt(2*2*3)=2*sqrt(3)
Add the three to get 9*sqrt(3)
Final answer:
9*sqrt(3)
Hope I helped :)

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