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koban [17]
3 years ago
7

The number of goats in a farm increases by 5 goats each year. If the farm has a population of 20 goats after the first year, and

n denotes the number of years, which recursive equation gives the population of goats, , as a function of the year?
Mathematics
1 answer:
MrRa [10]3 years ago
8 0

Answer:

f ( 1 )= 20; f ( n )= f (n - 1) + 5, for n > 2

(the > has a line under it)

Step-by-step explanation:

You might be interested in
Andrea Is selling candles as a fundraiser she spent $50 on supplies for making the candles she plans to sell candles for $10 eac
dalvyx [7]

COMPLETE QUESTION:

Andrea is selling candles as a fundraiser. She spent $50 on supplies for making the candles. She plans to sell the candles for $10 each. Her profit can be modeled by C(x) = 10x - 50.

What type of function is this?

What is the domain and range of the function?

Answer:

- This function is one-to-one

- Domain D = {x: x is a whole number ≤ Z}

- Range R = {y: y is in -50, ..., (10Z - 50)}

Where Z is the number of candles she could produce with $50.

Step-by-step explanation:

Given that her profit is modeled by C(x) = 10x - 50

- This function is one-to-one, because it is in the form f(x) = y.

Let the number of candles she could make with $50 be Z.

Then the domain is the set of all whole numbers less or equal to Z.

D = {x: x is a whole number ≤ Z}

If there are infinite number of candles she could make with that money, then

D = (-infinity, infinity)

When x = 0, we have C = -50

When x = Z, we have C = 10Z - 50

The range is then given as

R = whole numbers from -50 up to (10Z - 50)

R = {y: y is in (50 -Z), ..., (10Z - 50)}

If there are infinite number of candles she could make with that money, then

R = (-infinity, infinity)

6 0
2 years ago
How do you find the limit?
coldgirl [10]

Answer:

2/5

Step-by-step explanation:

Hi! Whenever you find a limit, you first directly substitute x = 5 in.

\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{5^2-6(5)+5}{5^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{25-30+5}{25-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{0}{0}}

Hm, looks like we got 0/0 after directly substitution. 0/0 is one of indeterminate form so we have to use another method to evaluate the limit since direct substitution does not work.

For a polynomial or fractional function, to evaluate a limit with another method if direct substitution does not work, you can do by using factorization method. Simply factor the expression of both denominator and numerator then cancel the same expression.

From x²-6x+5, you can factor as (x-5)(x-1) because -5-1 = -6 which is middle term and (-5)(-1) = 5 which is the last term.

From x²-25, you can factor as (x+5)(x-5) via differences of two squares.

After factoring the expressions, we get a new Limit.

\displaystyle \large{ \lim_{x\to 5}\frac{(x-5)(x-1)}{(x-5)(x+5)}}

We can cancel x-5.

\displaystyle \large{ \lim_{x\to 5}\frac{x-1}{x+5}}

Then directly substitute x = 5 in.

\displaystyle \large{ \lim_{x\to 5}\frac{5-1}{5+5}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{4}{10}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{2}{5}=\frac{2}{5}}

Therefore, the limit value is 2/5.

L’Hopital Method

I wouldn’t recommend using this method since it’s <em>too easy</em> but only if you know the differentiation. You can use this method with a limit that’s evaluated to indeterminate form. Most people use this method when the limit method is too long or hard such as Trigonometric limits or Transcendental function limits.

The method is basically to differentiate both denominator and numerator, do not confuse this with quotient rules.

So from the given function:

\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}

Differentiate numerator and denominator, apply power rules.

<u>Differential</u> (Power Rules)

\displaystyle \large{y = ax^n \longrightarrow y\prime= nax^{n-1}

<u>Differentiation</u> (Property of Addition/Subtraction)

\displaystyle \large{y = f(x)+g(x) \longrightarrow y\prime = f\prime (x) + g\prime (x)}

Hence from the expressions,

\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2-6x+5)}{\frac{d}{dx}(x^2-25)}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2)-\frac{d}{dx}(6x)+\frac{d}{dx}(5)}{\frac{d}{dx}(x^2)-\frac{d}{dx}(25)}}

<u>Differential</u> (Constant)

\displaystyle \large{y = c \longrightarrow y\prime = 0 \ \ \ \ \sf{(c\ \  is \ \ a \ \ constant.)}}

Therefore,

\displaystyle \large{ \lim_{x \to 5} \frac{2x-6}{2x}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{2(x-3)}{2x}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{x-3}{x}}

Now we can substitute x = 5 in.

\displaystyle \large{ \lim_{x \to 5} \frac{5-3}{5}}\\&#10;&#10;\displaystyle \large{ \lim_{x \to 5} \frac{2}{5}}=\frac{2}{5}

Thus, the limit value is 2/5 same as the first method.

Notes:

  • If you still get an indeterminate form 0/0 as example after using l’hopital rules, you have to differentiate until you don’t get indeterminate form.
8 0
2 years ago
Any of these??? the whole page? Please it's due in 2 hours and I would love the help!
Vinvika [58]
9.This is because it goes through the whole circle passing through the centre point. at the full width
The rest are pretty easy. I'm sure you can manage. Good luck!
6 0
3 years ago
A 12-foot board rests against a wall. The angle that the board makes with the ground is 60°. How far is the base of the board aw
denis-greek [22]

Answer:

A. cos 60° = ; x = 6 feet

Step-by-step explanation:

apex

7 0
2 years ago
Read 2 more answers
Divide 72kg in a ratio of 1:3:5
77julia77 [94]
Add together your portions 1 + 3 + 5 = 9 divide 72 by 9 = 8 Each portion is multiplied by 8 1 x 8 = 8 3 x 8 = 24 5 x 8 = 40 Your portions are 8kg:24kg:40kg Is this correct? Add 8 + 24 + 40. Do they equal 72? yes. Your portions are correct.
7 0
3 years ago
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