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Lady_Fox [76]
3 years ago
12

How long does it take a cup of fresh water to freeze, boil and evaporate compared to fresh water

Physics
1 answer:
eduard3 years ago
7 0
They exhibit identical behaviors with regard to changes of phase.
If there is any difference, it is too small to be measured, and none
has been observed.
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What are two ways in which friction can be useful?
pishuonlain [190]
If something is going down a hill it can help slow it down

it can stop you from flying off a rollercoaster
6 0
2 years ago
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How large a band of frequencies does each television broadcasting channel get ?
k0ka [10]

Answer:

Since the waves must carry a great deal of visual as well as audio information, each channel requires a larger range of frequencies than simple radio transmission. TV channels utilize frequencies in the range of 54 to 88 MHz and 174 to 222 MHz. (The entire FM radio band lies between channels 88 MHz and 174 MHz.)

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2 years ago
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When you go for a walk which of the following forces is paired with the force of friction on your shoe
Ann [662]

Answer:

static

Explanation:

static friction pushes in the direction you are walking.

7 0
3 years ago
A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.
JulsSmile [24]

Answer:

\mu =0.75

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

F_c=m.a_c

The centripetal acceleration a_c is computed as

\displaystyle a_c=\frac{v^2}{r}

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

F_c=m.\frac{v^2}{r}

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

F_r=\mu N

The normal force N is equal to the weight of the car, thus

F_r=\mu .m.g

Equating both forces

\displaystyle \mu .m.g=m.\frac{v^2}{r}

Simplifying

\displaystyle \mu =\frac{v^2}{rg}

Substituting the values

\displaystyle \mu =\frac{19^2}{(49)(9.8)}

\boxed{\mu =0.75}

7 0
3 years ago
What is the magnitude of the force that lifts a 3-kilogram object straight upwards?
frez [133]

Any force of 29.4 Newtons or greater can do it.

4 0
3 years ago
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