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ivann1987 [24]
3 years ago
7

Which of the following best represents potential energy being converted to kinetic energy? A. A man jogs and stops to drink an e

nergy drink. B. A drawn bow is released, causing an arrow to fly across a field. C. A roller coaster rounds a curve and climbs the next hill. D. A tree is struck by lightning, and then it is set on fire.
Physics
2 answers:
Schach [20]3 years ago
3 0
<span>So we want to know which of the following is the best representation of converting potential energy into kinetic energy. The correct answer is C. A roller coaster rounds a curve to climb the next hill. So before he climbed the hill, the roller coaster had kinetic energy which he used to climb to the hill. Then the potential energy he has on the hill can again be transformed into kinetic energy when he will go down hill. </span>
igomit [66]3 years ago
3 0

Answer;

B.  A drawn bow is released, causing an arrow to fly across the field.

Explanation;

Potential energy is the energy in a body due to its position. While kinetic energy is the energy in a body due to its motion. The formula for potential energy is mgh, where m stands for mass, g stands for gravitational acceleration and h stands for height.

Potential energy is the stored energy that can become kinetic energy. Kinetic energy is given by 1/2mv², where m is the mass and v is the velocity.

Potential energy = Stored energy, usually energy in bonds, energy in height.  

Kinetic energy = Energy of movement

As you draw the bow, the elasticity of the bow stores the energy (potential), and once you release, the arrow flies across the field (kinetic).

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A commonly used unit of mass in the English system is the pound-mass, abbreviated lbm, where 1 lbm = 0.454 kg. What is the densi
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Answer: The density of glycerine will be 0.028lbm/foot^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given:

Density of glycerine= 1.26\times 10^3kg/m^3

1 lbm = 0.454 kg

1 kg =\frac{1}{0.454}=2.2lbm

Thus 0.454kg=\frac{2.2}{1}\times 0.454=0.99

Also 1m^3=35.3147foot^3

Putting in the values we get:

Density=\frac{0.99lbm}{35.3147}=0.028lbm/foot^3

Thus density of glycerine will be 0.028lbm/foot^3

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The structure of which substances tends to exhibit the greatest hardness?
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2 years ago
To teach you how to find the parameters characterizing an object in a circular orbit around a much heavier body like the earth.
Karolina [17]

Answer:

a)  T² = (\frac{4\pi ^2}{GM})  r³

b) veloicity the dependency is the inverse of the root of the distance

kinetic energy  depends on the inverse of the distance

potential energy dependency is the inverse of distance

angular momentum depends directly on the root of the distance

Explanation:

1) for this exercise we will use Newton's second law

            F = ma

in this case the acceleration is centripetal

            a = v² / r

the linear and angular variable are related

           v = w r

we substitute

           a = w² r

force is the universal force of attraction

           F = G \frac{m M}{r^2}

we substitute

         G \frac{m M}{r^2} = m w^2 r

         w² = \frac{GM}{r^3}

angular velocity is related to frequency and period

         w = 2π f = 2π / T

we substitute

            ( \frac{2\pi }{T} ) = \frac{GM}{r^3}

the final equation is

             T² = ()  r³

b) the speed of the orbit can be found

           v = w r

            v = \sqrt{\frac{GM}{r^3} } \ r

            v = \sqrt{\frac{GM}{r} }

in this case the dependency is the inverse of the root of the distance

Kinetic energy

           K = ½ M v²

           K = ½ M GM / r

           K = ½ GM² 1 / r

the kinetic energy depends on the inverse of the distance

Potential energy

          U =

          U = -G mM / r

dependency is the inverse of distance

Angular momentum

          L = r x p

for a circular orbit

           L = r p = r Mv

           L =

         L =

The angular momentum depends directly on the root of the distance

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Forced-Air would be the type of central heating system 
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