Earth sits motionless in the universe at the center of a revolving globe of starts , with the moon and planets in orbit around the earth, is the surrounding model of the uninverse
Answer:
C = 4,174 10³ V / m^{3/4}
, E = 7.19 10² / ∛x, E = 1.5 10³ N/C
Explanation:
For this exercise we can calculate the value of the constant and the electric field produced,
Let's start by calculating the value of the constant C
V = C
C = V / x^{4/3}
C = 220 / (11 10⁻²)^{4/3}
C = 4,174 10³ V / m^{3/4}
To calculate the electric field we use the expression
V = E dx
E = dx / V
E = ∫ dx / C x^{4/3}
E = 1 / C x^{-1/3} / (- 1/3)
E = 1 / C (-3 / x^{1/3})
We evaluate from the lower limit x = 0 E = E₀ = 0 to the upper limit x = x, E = E
E = 3 / C (0- (-1 / x^{1/3}))
E = 3 / 4,174 10³ (1 / x^{1/3})
E = 7.19 10² / ∛x
for x = 0.110 cm
E = 7.19 10² /∛0.11
E = 1.5 10³ N/C
These are the Kepler's laws of planetary motion.
This law relates a planet's orbital period and its average distance to the Sun. - Third law of Kepler.
The orbits of planets are ellipses with the Sun at one focus. - First law of Kepler.
The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames. - Second law of Kepler.
Answer:
The moment of inertia is 
Explanation:
From the question we are told that
The frequency is 
The mass of the pendulum is 
The location of the pivot from the center is 
Generally the period of the simple harmonic motion is mathematically represented as

Where I is the moment of inertia about the pivot point , so making I the subject of the formula it
=> ![I = [ \frac{T}{2 \pi } ]^2 * m* g * d](https://tex.z-dn.net/?f=I%20%3D%20%20%5B%20%5Cfrac%7BT%7D%7B2%20%5Cpi%20%7D%20%5D%5E2%20%2A%20%20m%2A%20%20g%20%2A%20d)
But the period of this simple harmonic motion can also be represented mathematically as

substituting values


So
![I = [ \frac{2.174}{2 * 3.142 } ]^2 * 2.40* 9.8 * 0.380](https://tex.z-dn.net/?f=I%20%3D%20%20%5B%20%5Cfrac%7B2.174%7D%7B2%20%2A%203.142%20%7D%20%5D%5E2%20%2A%20%20%202.40%2A%20%209.8%20%2A%200.380)
