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ivann1987 [24]
3 years ago
7

Which of the following best represents potential energy being converted to kinetic energy? A. A man jogs and stops to drink an e

nergy drink. B. A drawn bow is released, causing an arrow to fly across a field. C. A roller coaster rounds a curve and climbs the next hill. D. A tree is struck by lightning, and then it is set on fire.
Physics
2 answers:
Schach [20]3 years ago
3 0
<span>So we want to know which of the following is the best representation of converting potential energy into kinetic energy. The correct answer is C. A roller coaster rounds a curve to climb the next hill. So before he climbed the hill, the roller coaster had kinetic energy which he used to climb to the hill. Then the potential energy he has on the hill can again be transformed into kinetic energy when he will go down hill. </span>
igomit [66]3 years ago
3 0

Answer;

B.  A drawn bow is released, causing an arrow to fly across the field.

Explanation;

Potential energy is the energy in a body due to its position. While kinetic energy is the energy in a body due to its motion. The formula for potential energy is mgh, where m stands for mass, g stands for gravitational acceleration and h stands for height.

Potential energy is the stored energy that can become kinetic energy. Kinetic energy is given by 1/2mv², where m is the mass and v is the velocity.

Potential energy = Stored energy, usually energy in bonds, energy in height.  

Kinetic energy = Energy of movement

As you draw the bow, the elasticity of the bow stores the energy (potential), and once you release, the arrow flies across the field (kinetic).

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A vacuum tube diode consists of concentric cylindrical electrodes, the negative cathode and the positive anode. Because of the a
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   C = 4,174 10³ V / m^{3/4} ,  E = 7.19 10² / ∛x,    E = 1.5  10³ N/C

Explanation:

For this exercise we can calculate the value of the constant and the electric field produced,

Let's start by calculating the value of the constant C

           V = C x^{4/3}

           C = V / x^{4/3}

            C = 220 / (11 10⁻²)^{4/3}

            C = 4,174 10³ V / m^{3/4}

To calculate the electric field we use the expression

            V = E dx

             E = dx / V

             E = ∫ dx / C x^{4/3}

            E = 1 / C  x^{-1/3} / (- 1/3)

            E = 1 / C (-3 / x^{1/3})

We evaluate from the lower limit x = 0 E = E₀ = 0 to the upper limit x = x, E = E

            E = 3 / C     (0- (-1 / x^{1/3}))

            E = 3 / 4,174 10³   (1 / x^{1/3})

           E = 7.19 10² / ∛x

for x = 0.110 cm

          E = 7.19 10² /∛0.11

          E = 1.5  10³ N/C

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A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.460 Hz. The pendulum ha
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Answer:

The  moment of inertia is  I =1.0697 \ kg m^2

Explanation:

From the question we are told that

    The  frequency is  f  =  0.460 \ Hz

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=>    I =  [ \frac{T}{2 \pi } ]^2 *  m*  g * d

But the period of this simple harmonic motion can also be represented mathematically as

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So

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      I =1.0697 \ kg m^2

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