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Wewaii [24]
3 years ago
11

Select the correct answer.

Physics
2 answers:
Kryger [21]3 years ago
6 0

Answer:

8.36*10^-4N/C

Explanation:

To find the electric field you use the following formula:

F=qE\\\\E=\frac{F}{q}

F: electric force = 8.2*10^-2 N

q: charge of the balloon = 9.4*10 C

By replacing F and q you obtain:

E=\frac{8.2*10^{-2}N}{9.4*10}=8.36*10^{-4}\frac{N}{C}

hence, the electric field is 8.36*10^-4N/C

kvasek [131]3 years ago
4 0

Answer:

8.37×10⁻⁴ N/C

Explanation:

Electric Field: This is the ratio of electrostatic force to electric charge. The S.I unit of electric field is N/C.

From the question, the expression for electric field is given as,

E = F/Q.......................... Equation 1

Where E = Electric Field, F = force experienced by the charged balloon, Q = Charge on the balloon.

Given: F = 8.2×10⁻² Newton, Q = 9.8×10 Coulombs = 98 Coulombs

Substitute these values into equation 1

E = 8.2×10⁻² /98

E = 8.37×10⁻⁴ N/C

Hence the Electric Field of the charged balloon =  8.37×10⁻⁴ N/C

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Answer:

The peak emf generated by the coil is 2.67 V

Explanation:

Given;

number of turns, N = 940 turns

diameter, d = 24 cm = 0.24 m

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time, t = 5 ms = 5 x 10⁻³ s

peak emf, V₀ = ?

V₀ = NABω

Where;

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B is the magnetic field strength

ω is the angular velocity

V₀ = NABω and ω = 2πf = 2π/t

V₀ = NAB2π/t

A = πd²/4

V₀ = N x (πd²/4) x B x (2π/t)

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V₀ = 940 x 0.04524 x  5 x 10⁻⁵ x 1256.8

V₀ = 2.6723 V = 2.67 V

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