Answer:
2 seconds
Explanation:
The function of height is given in form of time. For maximum height, we need to use the concept of maxima and minima of differentiation.
Differentiate with respect to t on both the sides, we get
For maxima and minima, put the value of dh / dt is equal to zero. we get
- 32 t + 64 = 0
t = 2 second
Thus, the arrow reaches at maximum height after 2 seconds.
Answer:
Position = behind the mirror
Nature = Virtual and Erect
Size = : Diminished
Explanation:
Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.
Object distance = u = -20 cm
Focal length = f = Radius of curvature/2 = 30/2 = 15 cm
We have to use mirror formula to find image distance.
Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.
Magnification =
Height of the object = 5 cm
Height of the image =
Since the height of the image is positive and less than the size of object,it is erect and diminished.