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Vera_Pavlovna [14]
3 years ago
5

A sample of carbon dioxide gas (CO2) contains 8.551 x 1025 molecules. How many moles of carbon dioxide does this represent?

Chemistry
1 answer:
ozzi3 years ago
8 0

Answer:

142.0 moles CO₂

Explanation:

To answer this question, we first need to know what a mole is. A mole represents 6.022 \cdot 10^{23} of something, and in this case, that something is molecules.

So, to convert 8.551 \cdot 10^{25} molecules into moles, we need to use the conversion factor  1=\frac{6.022\cdot 10^{23} \text{molecules} }{ \text{1 mole}}.

Doing so (using dimensional analysis) gives us:

8.551 \cdot 10^{25} \text{ molecules } \cdot  \frac{\text{1 mole}}{ 6.022\cdot 10^{23} \text{ molecules} } = \frac{8.551 \cdot 10^{25}}{ 6.022\cdot 10^{23}} \text{ moles CO}_2 = \\ \\ 141.996 \text{ moles CO}_2 = \boxed{142.0 \text{ moles CO}_2 }

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Answer:

Explanation:

The cell reaction properly written is shown below:

              Cu|Cu²⁺_{aq} || Ag⁺_{aq} | Ag

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  Oxidation half:

                  Cu_{s}  ⇄ Cu²⁺_{aq} + 2e⁻

At the anode, oxidation occurs.

  Reduction half:

                  Ag⁺_{aq} + 2e⁻ ⇄ Ag_{s}

At the cathode, reduction occurs.

To derive the overall reaction, we must balance the atoms and charges:

             Cu_{s}  ⇄ Cu²⁺_{aq} + 2e⁻

              Ag⁺_{aq} + e⁻ ⇄ Ag_{s}

  we multiply the second reaction by 2 to balance up:

         2Ag⁺_{aq} + 2e⁻ ⇄ 2Ag_{s}

The net reaction equation:

Cu_{s} + 2Ag⁺_{aq} + 2e⁻⇄ Cu²⁺_{aq} + 2e⁻ + 2Ag_{s}

We then cancel out the electrons from both sides since they appear on both the reactant and product side:

  Cu_{s} + 2Ag⁺_{aq} ⇄ Cu²⁺_{aq} + 2Ag_{s}

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3 years ago
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Explanation:

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