Answer:
8.5 moles of Al₂O₃ will formed
Explanation:
Given data:
Number of moles of Al = 17 mol
Number of moles of Al₂O₃ formed = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Now we will compare the moles of Al₂O₃ with Al.
Al : Al₂O₃
4 : 2
17 : 2/4×17 = 8.5 mol
8.5 moles of Al₂O₃ will formed.
First solve the moles of oxgen present in the compound
mol O = 6.93 g O ( 1 mol O / 16 g O )
mol O = 0.43 mol H
then solve the moles of hydrogen present
mol H = ( 7.36 - 6.93) g H ( 1 mol H / 1 g H)
mol H = 0.43 mol H
so the O and H are in the same mole content so the molecular formula would be OH, but the molar mass will not satisfy. so the answer would be
H2O2
respiratory and lymphatic
Answer:
The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.
Explanation:
Assume that ethane behaves as an ideal gas under these conditions.
By the ideal gas law,
,
.
where
is the pressure of the gas,
is the volume of the gas,
is the number of moles of particles in this gas,
is the ideal gas constant, and
is the absolute temperature of the gas (in degrees Kelvins.)
The numerical value of
will be
if
,
, and
are in SI units. Convert these values to SI units:
;
shall be in cubic meters,
;
.
Apply the ideal gas law:
.
I’m pretty sure it would be D.