Formula of kinetic energy = 0.5*mass*velocity squared so the answer is 11008j
Answer:
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Explanation:
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Incomplete question.The complete question is here
Determine the torque applied to the shaft of a car that transmits 225 hp and rotates at a rate of 3000 rpm.
Answer:
Torque=0.51 Btu
Explanation:
Given Data
Power=225 hp
Revolutions =3000 rpm
To find
T( torque )=?
Solution
As
As force moves an object through a distance, work is done on the object. Likewise, when a torque rotates an object through an angle, work is done.
So
Answer: 210.2N
Explanation:
Assume a bucket of water with a total mass of 68kg is attached to a rope, which in turn is tied around a 0.078m radius cylinder at the top of a well. A crank with a turning radius of 0.250 m is attached to the end of the cylinder.
the minimum force directed perpendicular to the crank handle required to raise the bucket is
(Assume the rope's mass is negligible, that the cylinder turns on friction-less bearings, and that g = 9.8 m/s2
The crank handle provides a torque T=0.25F where F is the force we are looking for.
A free body diagram will show that the tension in the rope times the cylinder radius R is equal to the torque on the cylinder. But the tension in the rope is just the weight of the bucket
W=mg= 68kg
W(0.078)=T=0.25F
F=0.312W=0.312(68kg)=21.216kg= 210.2N
