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bagirrra123 [75]
3 years ago
13

Calculate the number of milliliters of 0.440 M KOH required to precipitate all of the Fe2+ ions in 187 mL of 0.692 M FeSO4 solut

ion as Fe(OH)2. The equation for the reaction is: FeSO4(aq) + 2KOH(aq) Fe(OH)2(s) + K2SO4(aq)
Chemistry
1 answer:
EleoNora [17]3 years ago
6 0

Answer:

588.2 mL

Explanation:

  • FeSO₄(aq) + 2KOH(aq) → Fe(OH)₂(s) + K₂SO₄(aq)

First we <u>calculate how many Fe⁺² moles reacted</u>, using the given <em>concentration and volume of FeSO₄ solution</em> (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):

  • moles = molarity * volume
  • 187 mL * 0.692 M = 129.404 mmol Fe⁺²

Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:

  • 129.404 mmol Fe⁺² * \frac{2mmolKOH}{1mmolFeSO_4} = 258.808 mmol KOH

Finally we<u> calculate the required volume of KOH solution</u>, using <em>the given concentration and the calculated moles</em>:

  • volume = moles / molarity
  • 258.808 mmol KOH / 0.440 M = 588.2 mL
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Schach [20]

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Explanation:

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2 years ago
How many moles of Fluorine (F2) are<br><br> needed to completely react 8.0<br><br> moles of NF3?
Anna [14]

Answer:

12 moles of F₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3F₂ —> 2NF₃

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Finally, we shall determine the number of mole of F₂ needed to produce 8 moles of NF₃. This can be obtained as illustrated below:

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, Xmol of F₂ will react to produce 8 moles of NF₃ i.e

Xmol of F₂ = (3 × 8)/2

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Thus, 12 moles of F₂ is needed for the reaction.

8 0
2 years ago
A scuba tank has a pressure of 195 KPa at a temperature of 10 °C. The volume of the tank is 350 L. How many grams of air is in t
marissa [1.9K]

The mass of air in the scuba tank is 841.614 g.

Using the ideal gas equation;

PV=nRT

P = pressure of the gas = 195 kPa

V = volume of the gas =  350 L

n = Number of moles of the gas = ??

R = molar gas constant = R = 8.314 J K-1 mol-1

T = temperature of the gas =  10 °C or 283 K

n = PV/RT

n = 195 * 350/8.314 * 283

n = 68250/2352.862

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Number of moles = mass/molar mass

mass of air = Number of moles * molar mass

mass of air = 29.00 moles * 29g/mol

Mass of air = 841.614 g

Learn more: brainly.com/question/4147359

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Answer:

En total son 8 modelos, en la explicación los nombraremos por orden de antigüedad.

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Modelo atómico de Demócrito (450 a.C.)

Modelo atómico de Dalton (1803 d.C.)

Modelo atómico de Lewis (1902 d.C.)

Modelo atómico de Thomson (1904 d.C.)

Modelo atómico de Rutherford (1911 d.C.)

Modelo atómico de Bohr (1913 d.C.)

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