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just olya [345]
3 years ago
12

Two descriptions for a sub-atomic particle are listed below: Description 1: Non-charged particle Description 2: Located inside t

he nucleus of an atom Which sub-atomic particle or particles fit these descriptions? Electrons only Neutrons only Electrons and protons Protons and neutrons
Chemistry
2 answers:
Juliette [100K]3 years ago
8 0

Answer:

Description 1: non-charged particle: Neutrons only

Description 2: Located inside the nucleus of an atom: Protons and neutrons

Explanation:

The subatomic particles of an atom are smaller than the atom, and the main are:

  • <em>Protons</em>: they are <em>positively charged</em> and are located <em>inside the nucleus</em> of an atom.
  • <em>Neutrons</em>: they are <em>neutral</em> and are also located <em>inside the nucleus</em> of an atom.
  • <em>Electrons:</em> they are <em>negatively charged</em> and they are in <em>the periphery of the nucleus</em> at unknown pathways.
Triss [41]3 years ago
6 0
Your answer should be protons,and neutrons.
: )

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7.The equation below shows a process that occurs in all green plants.
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Ⓓ The process follows the law of conservation of mass and energy is found in the product

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How much rust is produced with 1.5 kg of Fe reacts with water
ZanzabumX [31]

Answer:

2071g or 2.071kg of rust (Fe3O4)

Explanation:

Step 1:

The balanced equation for the reaction.

3Fe + 4H2O —> Fe3O4 + 4H2

Step 2:

Determination of the mass of Fe that reacted and the mass of the Fe3O4 produced from the balanced equation.

Molar Mass of Fe = 56g/mol

Mass of Fe from the balanced equation = 3 x 56 = 168g

Molar mass of Fe3O4 = (56x3) + (16x4) = 232g/mol

Mass of Fe3O4 from the balanced equation = 1 x 232 = 232g

Summary:

From the balanced equation above,

168g of Fe reacted and 232g of Fe3O4 was produced.

Step 3:

Determination of the mass of rust (Fe3O4) produced when 1.5kg ( i.e 1500g) of Fe reacted.

This is illustrated below:

From the balanced equation above,

168g of Fe reacted to produce 232g of Fe3O4.

Therefore, 1500g of Fe will react to produce = (1500x232)/168 = 2071g of Fe3O4.

From the calculations made above, 2071g or 2.071kg of rust (Fe3O4) is produced.

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3 years ago
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