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Brut [27]
3 years ago
14

Give two example for desert plants and animals?please mark as brainliest​

Chemistry
2 answers:
aev [14]3 years ago
8 0

Answer:

Plants : Cactus, tumbleweed

Animals : camel, fennec fox

Fittoniya [83]3 years ago
7 0

Answer:

Desert plant - Cactus & Tumbleweed

Desert animal - Camel & Scorpion

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1. Which is not an example of matter? (6.P.2.1) *<br> Water<br> Mrs. Saliba<br> Imagination<br> Air
Alchen [17]

Answer:

Imagination

Explanation:

This isnt a real object

Hope this helps

3 0
3 years ago
Determine the mass of a ball with a wavelength of 3.45 × 10-34 m and a velocity of 6.55 m/s
Yuki888 [10]
<span>293 grams The formula for the wavelength of a massive particle is λ = h/p where λ = wavelength h = Plank constant (6.626070040Ă—10^â’34 J*s) p = momentum (mass times velocity) So let's solve for momentum and from there get the mass λ = h/p λp = h p = h/λ Substitute known values and solve p = 6.626070040Ă—10^â’34 J*s/3.45Ă—10^-34 m p = 1.92 J*s/m Since momentum is the product of mass and velocity, we have p = M * V p/V = M So substitute again, and solve. p/V = M 1.92 J*s/m / 6.55 m/s = M 1.92 kg*m/s / 6.55 m/s = M 1.92 kg*m/s / 6.55 m/s = M 0.293 kg = M So the mass is 293 grams</span>
6 0
4 years ago
Read 2 more answers
Chemistry
Katena32 [7]

When a solid turns into a liquid

Example: Ice cube melts into water

4 0
3 years ago
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A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is
Charra [1.4K]

Answer:

[H^{+}] = 0.761 \frac{mol}{L}

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

pH = 0.119

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L)  \\ n_{H^{+} } from HNO_{3}  = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

n_{H^{+} } from HCl = (5.00)(0.093)

n_{H^{+} } from HCl = 0.465 mol

n_{H^{+} } from HNO_{3}  = (8.00)(0.037)

n_{H^{+} } from HNO_{3}  = 0.296 mol

n_{H^{+}(total) } = 0.296 + 0.465

n_{H^{+}(total) } = 0.761 mol

For molar concentration of hydrogen ions:

[H^{+}]  = \frac{n_{H^{+}}(mol)}{V(L)}

[H^{+}] = \frac{0.761}{1.00}

[H^{+}] = 0.761 \frac{mol}{L}

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

K_{w} = [H^{+} ][OH^{-} ]

[OH^{-}]=\frac{Kw}{[H^{+}] }

[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

The pH of the solution can be measured by the following formula:

pH = -log[H^{+} ]

pH = -log(0.761)

pH = 0.119

5 0
3 years ago
What is the most likely meaning of concentration in paragraph 7?thinking thinking about about one one thing thing in in a a focu
astraxan [27]

Answer:

amount of a substance found in water.

6 0
3 years ago
Read 2 more answers
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